3x^2+11x-4=10x-1
3x^2+11x-10x-4+1=0
3x^2+x-3=0
Δ=1^1-4*3*(-3)=1+36=37
x1=(-1+V37)/6
x2=( -1-V37)/6
Answer:
First, find the bats left 100 times for left-handed pitchers and right-handed pitchers:
0.285 x 100 = 28.5
0.175 x 100 = 17.5
Next, subtract these numbers to find how many more hits he will get:
28.5 - 17.5 = 11 and that is your answer
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