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gavmur [86]
3 years ago
8

Which of the following is the greatest dissolved solid in ocean water? Magnesium Chloride Plankton Sodium Chloride Calium

Chemistry
1 answer:
melisa1 [442]3 years ago
8 0

The right answer is Sodium chloride.

Sodium chloride is a chemical compound whose formula is NaCl. Everyone knows the taste because it is, more simply, table salt.

Let's take a pool 50 meters long and 15 meters wide and fill it with sea water. Then let's go to his analysis. We find:

1400 tons of pure water

50 tons of sodium chloride

2 tons of magnesium

1 ton of sulfur

And then much less frequent elements

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Worksheet Ch.3: % Composition, Molarity, and Other Units for
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The percentage composition by mass of the elements in the compound are:

Ai. The percentage composition by mass of Na in 3.65 g of NaF is 54.8%

Aii. The percentage composition by mass of F in 3.65 g of NaF is 45.2%

Bi. The percentage composition by mass of Zinc in the compound is 67.1%

Bii. The percentage composition by mass of Sulfur in the compound is 32.9%

Percentage composition by mass of an element in a compound can be obtained by using the following formula:Percentage = \frac{mass of Element}{mass of compound}  * 100

Ai. Determination of the percentage of Na in 3.65 g of NaF

Mass of Na = 2 g

Mass of NaF = 3.65 g

<h3>Percentage of Na =? </h3>

Percentage = \frac{mass of element }{mass of compound} * 100\\\\Percentage of Na = \frac{2}{3.65} * 100

<h3>Percentage of Na = 54.8%</h3>

Aii. Determination of the percentage of F in 3.65 g of NaF

Mass of F = 1.65 g

Mass of NaF = 3.65 g

<h3>Percentage of F =? </h3>

Percentage = \frac{mass of element }{mass of compound } * 100\\\\Percentage of F = \frac{1.65}{3.65} * 100\\\\

<h3>Percentage of F = 45.2%</h3>

Bi. Determination of the percentage composition of Zn in 48.72 g of the compound

Mass of Zn = 32.69 g

Mass of compound = 48.72 g

<h3>Percentage of Zn =? </h3>

Percentage = \frac{mass of element}{mass of compound} * 100\\\\Percentage of Zn = \frac{32.69}{48.72} *100\\\\

<h3>Percentage of Zn = 67.1%</h3>

Bii. Determination of the percentage composition of Sulphur in 48.72 g of the compound

Mass of Zn = 32.69 g

Mass of compound = 48.72 g

Mass of S = 48.72 – 32.69 g

Mass of S = 16.03 g

<h3>Percentage of S =? </h3>

Percentage = \frac{mass of element}{mass of compound}  * 100\\\\Percentage of S = \frac{16.03}{48.72}  * 100\\\\

<h3>Percentage of S = 32.9%</h3>

Learn more: brainly.com/question/1350382

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