he arsenic acid or arsenate hydrogen as it is also known to this compound (H 3 AsO 4 ) is the acid form of <span>ion </span>arsenate , AsO<span>4 </span>3- , one anion trivalent in which arsenic has an oxidation state of + 5. Chemically, arsenates behave in a similar way tophosphates .
There is another compound derived from this one that is the arsenious acid or arsenite of hydrogen
Answer:
The amount of work done on the system is 18234 J and the final positive sign means that this work corresponds to an increase in internal energy of the gas.
Explanation:
Thermodynamic work is called the transfer of energy between the system and the environment by methods that do not depend on the difference in temperatures between the two. When a system is compressed or expanded, a thermodynamic work is produced which is called pressure-volume work (p - v).
The pressure-volume work done by a system that compresses or expands at constant pressure is given by the expression:
W system= -p*∆V
Where:
- W system: Work exchanged by the system with the environment. Its unit of measure in the International System is the joule (J)
- p: Pressure. Its unit of measurement in the International System is the pascal (Pa)
- ∆V: Volume variation (∆V = Vf - Vi). Its unit of measurement in the International System is cubic meter (m³)
In this case:
- p= 10 atm= 1.013*10⁶ Pa (being 1 atm= 101325 Pa)
- ΔV= 2 L- 20 L= -18 L= -0.018 m³ (being 1 L=0.001 m³)
Replacing:
W system= -1.013*10⁶ Pa* (-0.018 m³)
Solving:
W system= 18234 J
<u><em>The amount of work done on the system is 18234 J and the final positive sign means that this work corresponds to an increase in internal energy of the gas.</em></u>
1 is b 2 is a 3 is d 4 is a 5 is c
277.79 atm is the calculated gas pressure.
The ideal gas is a fictitious concept used to study how real gases behave by comparing them to their deviations. The pressure-temperature rules are followed by an ideal gas.
177 atm is the initial pressure. The starting temperature is 298 K (25 °C = 25 + 273 °C).
195°C = 195+273
= 468K is the final temperature.
The pressure temperature relation illustrated below can be used to get the final pressure.
P1/T1 = P2/T1
= P1T2/T1
= 177 atm 468 K /298 K
= 277.97 atm
The final pressure is therefore 277.97 atm.
Learn more about Pressure here-
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