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USPshnik [31]
3 years ago
10

The correct value according to Ruler A is 2.2 cm

Chemistry
1 answer:
vladimir2022 [97]3 years ago
3 0

Answer:

Measure the diameter of the circle using Ruler A and Ruler B.

Given that the actual diameter of the circle is 2.264 cm, classify the following statements that describe the diameter measurement of the circle according to the ruler.

Drag the appropriate items to their respective bins.

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Carbon -11 is a radioactive isotope of carbon. It’s half life is 20 minutes. What amount of the initial mass of 70.0g of C -11 a
dusya [7]

Answer:

4.38g

Explanation:

70.0/2 = 35g - 20 mins

35/2 = 17.5g - 40 mins

17.5/2 = 8.75g - 60 mins

8.75/2 = 4.375g - 80 mins

6 0
3 years ago
Analyze complete and balance the following equation co2(g)+hcl(aq)
Anna007 [38]

Answer:

CO_{2} (g)+4HCl(aq)->2H_{2} O(g)+CCl_{4} (g)

This is a double displacement reaction, C goes with Cl in the products side and O2 goes with H. All that is left is to balance the equation, making sure each side has equal amounts of atoms.

4 0
3 years ago
A golf pro has 2100 J of kinetic energy and swings his driver which weighs .75 kg. What is the speed of his swing?
jeka57 [31]

Answer : The correct answer is 74.83 m/s .

The kinetic energy is energy possessed by any mass which is moving or have some speed . It is product of mass and velocity . It is expressed as :

KE = \frac{1}{2}  * m* v^2

Where KE = kinetic energy in J or kg\frac{m^2}{s^2} m = mass in Kg v = speed in m/s²

Unit of KE is Joules (J) .

Givne : KE = 2100 J mass = 0.75 kg v = ?

Plugging value in KE formula =>

2100 J = \frac{1}{2}  * 0.75 Kg * v^2

2100 J = 0.375 Kg * v^2

Dividing both side by 0.375 kg =>

\frac{2100 J}{0.375 Kg}  = \frac{0.375 Kg}{0.375 Kg } * v^2

v^2 = 5600 \frac{m^2}{s^2}

v= 74.83 \frac{m}{s}

8 0
4 years ago
Read 2 more answers
Can someone help me answer these 2 questions
SSSSS [86.1K]

The Water Biome has The most biodiversity. The Desert is diffrent from the Tundra Tundra and deserts both face a scarcity in water. Therefore, the vegetation found in either biome are adapted to live in such water-barren environments. The vegetation of the tundra is also resistant to cold temperatures and winds. ... Many succulents are found in a hot and dry desert.

4 0
3 years ago
If hydrogen were used as a fuel, it could be burned according to the following reaction: H2(g)+1/2O2(g)→H2O(g). Use average bond
serious [3.7K]
The deltaHrxn = -243 kJ/mol the deltaHrxn of CH4(methane) = -802 kJ/mol 

The fuel that yields more energy per mole is METHANE. The negative sign merely signifies the release of energy. Thus, 802 kJ/mol is greater than 243 kJ/mol.

The fuel that yields more energy per gram is HYDROGEN. Here is the computation:
deltaHrxn = (-243 kJ/mol)(1 mol/2.016 g H2)  <span>= -120.535714286 kJ/g or -121 kJ/g

</span>deltaHrxn of CH4(methane) = (-802 kJ/mol)(1 mol/16.04 g) 
<span>= -50 kJ/g 
</span>
As discussed the negative sign serves as the symbol of released energy. Thus, 121 is greater than 50.
7 0
3 years ago
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