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4 years ago

Two symptoms are associated with a certain disease.

Mathematics

1 answer:

Bezzdna [24]4 years ago

5 0

Answer:

Mutually exclusive, dependent events

Step-by-step explanation:

Two events A and B are mutually exclusive if $P(A\cap B)=0$

Two events A and B are independent if $P(A\cap B)=P(A)\cdot P(B)$

Remark: All mutually exclusive events are dependent.

Now,

A = the first symptom occurs

B = the second symptom occurs

$P(A)=0.5\ (\text{or } 50\%)$

$P(B)=0.45\ (\text{or } 45\%)$

$P(A\cup B)=0.95 \ (\text{or }95\%)$

Use the rule

$P(A\cup B)=P(A)+P(B)-P(A\cap B)\\ \\0.95=0.5+0.45-P(A\cap B)\\ \\P(A\cap B)=0.5+0.45-0.95=0.95-0.95=0$

Thus, the events A and B are mutually exclusive (disjoint) and dependent (accordint to the remark)

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15PTS PLEASE HELP ASAP!! (dont write random answers pls!)

ikadub [295]

Answer:

to find the answer, you need to find the measure of the angle on the other side of the 142. and since it's a straight line, those two angles measures are =to 180 (they're supplementary angles). so the measure of that angle is 38 degrees. to find the measure of the remaining angle, you subtract the angle measures you already know from 180 (because the sum of interior angles in a triangle is 180.) to, the answer is:

180-90-38= 52 degrees or A

7 0

3 years ago

Based on the information marked in the diagram, AABC and ADEF must be

Studentka2010 [4]

Answer:

Step-by-step explanation:

answer

8 0

3 years ago

PLEASE ANSWER QUICKLY

Olegator [25]

Answer:

x=3

Step-by-step explanation:

Set equations equal to each other:

$x^3-3x^2+2=x^2-6x+11$

Subtract two from both sides

$x^3-3x^2=x^2-6x+9$
Factor out x^2 from the left side

$x^2(x-3)=x^2-6x+9$

Factor the right side, look for two factors of 9, which add to -6, which is just -3 and-3

$x^2(x-3) = (x-3)(x-3)$

So as you can see here, we have both sides in factored form, and both have a factor of (x-3) on both sides, and if one of the factors is zero, then the entire thing becomes zero, since 0 * anything= zero.

this means a solution would be at x=3, since it makes the right side 0 * 0 = 0, and the left side (3)^2 * 0 = 0

It's important to notice this, since had we divided by x-3 to make the equation a quadratic, we would've excluded this real solution, because when dividing by x-3 the solution x=3 makes it 0, so we would've been dividing by zero.

So one of the real solutions is at x=3

6 0

2 years ago

The Question Is:

lora16 [44]

Answer:

C) ∠3 and ∠6 is the CORRECT OPTION.

Step-by-step explanation:

Here, the image is UNATTACHED. Attaching image here for the reference.

Given: JL and MP are parallel.

Alternate Interior angles is a pair of angles formed when there is a common intersecting line between two parallel lines.

As JL and MP are parallel.

and KN is a traversal. So, the pair of Alternate Interior angles so formed are:

a) ∠3 and ∠6

b) ∠4 and ∠5

Now, out of the given options:

A. ∠3 and ∠4 is a LINEAR PAIR

B. ∠1 and ∠6 makes no pair

C. ∠3 and ∠ 6 is a Alternate Interior angles pair

D. ∠5 and ∠6 LINEAR PAIR

Hence, ∠3 and ∠ 6 is a Alternate Interior angles pair.

3 0

4 years ago

Hayley is considering two gym membership plans. The plans are detailed here.

mote1985 [20]

Plan 1: $50 for a monthly pass and a $3 fee for each gym visit

So, the monthly pass is 50 plus 3 for each visit. You know 50 stays constant no matter how much Hayley goes to the gym so you can already put that into the form as 'b' also known as the y-intercept.

y=mx+50

Now, you need to find the slope which is the amount it increases or decreases by every time. Since Hayley gets charged $3 every visit, that would be the slope (m).

Plan 1: y=3x+50

---------------------------------------------------------

Plan 2: $10 for each gym visit

There is only a slope (m) for this. Technically there is a y-intercept (b), but since that is 0 it is not needed. Plug in the values.

y=mx+b
y=10x

6 0

3 years ago