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3 years ago

Help plz math is my worst subject i have a lot of over due work

Mathematics

1 answer:

zubka84 [21]3 years ago

5 0

I believe the answer is the first option. 1 to 3 with intervals of 1.
Hope this helps!

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Solve each equation.Show your work.<br>Can someone help me please??

Inga [223]

Answer:

1/2a = -5

a = (-5 x 2) : 1

a = -10

8 - b = 9,5

b = 8 - 9,5

b = -1,25

0,1 = -10c

c = 0,1 : -10

c = -0,01

I hope it's helpful.

3 0

3 years ago

Help please only in number 15!!!!!$ thank youuuuuu

hodyreva [135]

This is the answer...

y=250-25x
y=30+30x

5 0

2 years ago

Will someone please tell me step by step how to solve this.

Gwar [14]

I believe you set them equal to each other.
2x+4=5x-9
x=4.3
2(4.3)+4=12.6
I think the answer is 12.6

6 0

2 years ago

For the functions f(x)=−7x^2−x and g(x)=9x^2−4x, find (f−g)(x) and (f−g)(1)

musickatia [10]

Answer:

See below.

Step-by-step explanation:

$f(x)=-7x^2-x\\g(x)=9x^2-4x\\(f-g)(x)=f(x)-g(x)\\(f-g)(x)=(-7x^2-x)-(9x^2-4x)\\(f-g)(x)=-7x^2-x-9x^2+4x\\(f-g)(x)=-16x^2+3x\\\\(f-g)(1)=-16(1)^2+3(1)\\(f-g)(1)=-16+3=-13$

5 0

3 years ago

Giving brainliest!!

slamgirl [31]

Answer:

Gah! Inverses!

Step-by-step explanation:

This is a pretty simple concept, just switch the x and f(x) values!

If you don't understand, look at how I solve it!

$f(x)=\frac{1}{3} -\frac{1}{21} x$

Switching the positions of the x and f(x) values...

$x=\frac{1}{3} -\frac{1}{21} f(x)^{-1}\\$

Note: That f(x)^-1 is the proper notation for inverse functions.

$x-\frac{1}{3} =-\frac{1}{21} f(x)^{-1} \\f(x)^{-1}=-21x+7$

There you go!

Hope this helps, and don't procrastinate!

7 0

3 years ago