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SOVA2 [1]
4 years ago
15

TechWiz Electronics makes a profit of $35 for each MP3 player sold and $18 for each DVD player sold. Last week, TechWiz sold a c

ombined total of 143 MP3 and DVD players. Let x be the number of MP3 players TechWiz sold last week. Write an expression for the combined total profit (in dollars) TechWiz made from MP3 and DVD players last week.
Mathematics
1 answer:
Lerok [7]4 years ago
5 0

Answer:

35x+18=143

      -18  -18

35x=125

/35   /35

x=3.60

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A.) 200cm
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A explanation.) To find the mean, you add all the heights and divide by 5 (how many numbers there are), this gives you 1000 divided by 5, which equals exactly 200cm.

B explanation.) I tried the equation with numbers higher than 202, going up one each time, and 206 was the one that equaled exactly 201.
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HELP! SHOW YOUR WORK!<br> 2 2/7 - 5 5/7
konstantin123 [22]

Answer:

-24/7

Step-by-step explanation:

change the number to improper fractions:

2 2/7 - 16/7

5 5/7 - 40/7

now since they wont make a positive number, you can do 40-16 which is 24 so your answer is -24/7

NEGATIVE 24/7

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3 years ago
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disa [49]

365 days are in a year

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3 years ago
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Jordan is chopping wood for the winter. For 10 days in a row, he follows the same process: In the morning, he chops 20 pieces of
Ronch [10]

i would write this:

total = 10(20+30) +5

8 0
4 years ago
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following frequency distribution shows the daily expenditure on milk of 30 households in a locality:Daily expenditure on milk(in
valina [46]

<em>Note:</em> <em>As you missed to identify what we have to find in this question. But, after a little research, I am able to find that we had to find the Mode for the data given in your question. So, I am assuming we have to calculate the the Mode. Hopefully, it would clear your concept regarding this topic.</em>

Answer:

The mode of the data = 75

Step-by-step explanation:

Lets visualize the given data in a table to show the frequency distribution:

<em>Daily expenditure on milk (in Rs)           Number of households</em>

<em>                  0-30                                                           5</em>

<em>                 30-60                                                          6        </em>

<em>                 60-90                                                          9</em>

<em>                 90-120                                                         6</em>

<em>                 120-150                                                        4</em>

Here the maximum frequency is 9.

So, modal class is <em>60-90.</em>

<em />

As the formula to calculate the mode:

Mode = l_{1} + h (\frac{f_{1}-f_{0}}{2f_{1}-f_{0}-f_{2}} )

Here, the maximum

l_{1} =60, f_{1} =9, f_{0}=6, f_{0}=6, h=30

l= is the lower limit of the class

f_{1} = is the frequency of the modal class

f_{0} = is the frequency of the previous modal class

f_{2} = is the frequency of the next previous modal class

l= is the class size

So,

Mode = l_{1} + h (\frac{f_{1}-f_{0}}{2f_{1}-f_{0}-f_{2}} )

Mode = 60 + 30 (\frac{9-6}{2(9)-6-6} )

Mode = 60 + \frac{(30)(3)}{6}

Mode = 60 + 15=75

∴ The mode of the data = 75

<em>Keywords: mode, frequency distribution</em>

<em> Learn more about mode and frequency distribution from brainly.com/question/14354368</em>

<em> #learnwithBrainly </em>

5 0
3 years ago
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