$\begin{aligned}&2 x^{4}-72 x^{2}=0 \\&2 x^{2}\left(x^{2}-36\right)=0 \\&x^{2}\left(x^{2}-36\right)=0 \\&x \times x \times(x-6) \times(x+6)=0 \\&\mathrm{x}=0,0,6,-6\end{aligned}$

So,

x = 0 multiplicity 2

x = -6 multiplicity 1

x = 6 multiplicity 1

For an even multiplicty, the graph touches the x-axis, and for an odd multiplicty, the graph crosses the x-axis

Therefore,

x = 0 multiplicty 2, Touch

x = -6 multiplicty 1, Cross

x = 6 multiplicty 1, Cross

7 0

2 years ago

Plz help me. Simplify:

alekssr [168]

Answer:

-14/1-5x

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Rachel bought a corn dog and three candy bars for $5.75. Allison bought two corn dogs and two candy bars for $7.50.

andreev551 [17]

Answer:

Step-by-step explanation:

4 0

2 years ago

Jessie bought 12 cases of soda for the party. If his total bill was $41.40, how much did each case cost?

jeka57 [31]

Answer:

B. $3.45

Step-by-step explanation:

Number of cases of soda bought = 12

Total bill payed = $41.40

Let x represent the cost of 1 case.

Thus:

12x = $41.40

Divide both sides by 12

12x/12 = 41.40/12

x = 3.45

Cost of each case = x = $3.45

4 0

2 years ago