Answer:
Okay so I am not positive but I will try to help you out. Okay so the line of best fit would positive. Because it is all going up. The approximate slope is 3/4 Because slope is change in y over change in x. The y intercept of the line of best fit would be (0,0). This is because when drawing the line you can see that it would intercept the y-axis at zero. My steps taken were basically just looking at it and peicing everything together. If you want to get more involved with slope you could pick to coordinates which I will include and do change in y over change in x.
My points I will pick are (1,1) and (5,2)
2-1/5-1=3/4
therefore approximate slope is 3/4
Like I said I am not positive but I am just trying to help out in some way.
If something is incorrect please inform me. If this helps also please inform me.
X= 5 and it also equals -5
Explanation:
All of these are done the same way.
1. Set your compass to a distance slightly longer than the distance from the point to the line you want the perpendicular to.
2. Using the point as a center, draw an arc that intersects the line in 2 places. Consider those points to be "P" and "Q".
3. You can leave the compass as is, or set it to any other distance longer than half the distance between P and Q. Using this radius, and using P and Q as centers, draw intersecting arcs on the other side of the line from the original point. Consider the intersection of those arcs to be point "R".
4. A line through the original point and point R will be perpendicular to the line, as you want.
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In problem 1, the point and line are obvious.
In problem 2, the point is the vertex opposite the line of interest. (There will be 3 similar constructions.)
