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3 years ago

Wath the square root of 12

Mathematics

2 answers:

melamori03 [73]3 years ago

8 0

The square root of 12 is 3.46410161 but you would round it so it’s 3.47

Alla [95]3 years ago

5 0

Hi! Your answer is:

√12 = approximately 3.4641

Also, the answer could be 2√3

Hope this helps!

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2.Solve x squared - 4x by Factoring

777dan777 [17]

Answer:

Step-by-step explanation:

hello:

x²-4x=0 means : x(x-4)=0

x=0 or x-4=0

conclusion : x=0 and x= 4 ...answer : B

8 0

3 years ago

A right circular cylinder has a height of 22 1/4 ft and a diameter 2 2/5 times its height. What is the volume of the cylinder? E

Triss [41]

Answer:

The volume of cylinder is:

49806.06 ft^3

Step-by-step explanation:

We are given a right circular cylinder with:

Height(h)= $22\frac{1}{4}ft=\dfrac{89}{4}ft$

and a diameter is $2\frac{2}{5}$ times it's height.

i.e. $\dfrac{12}{5}$ times it height.

i.e. the diameter is given as:

$\dfrac{12}{5}\times \dfrac{89}{4}=\dfrac{267}{5}ft.$

We know that the radius of cylinder is half the diameter.

Hence, radius(r) of cylinder is:

$\dfrac{1}{2}\times \dfrac{267}{5}\\\\=\dfrac{267}{10}$

The volume(V) of cylinder is given by:

$V=\pi r^2h$

$V=3.14\times (\dfrac{267}{10})^2\times \dfrac{89}{4}\\\\V=\dfrac{19922423.94}{400}\\\\V=49806.06ft^3$

Hence, the volume of cylinder is:

49806.06 ft^3

7 0

4 years ago

Find the value of given expression<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B31%20-%20%28%20-%205%29%7D%20" id="TexF

Neko [114]

31-(-5) = 155
the square root of 155 is 12.45

4 0

3 years ago

Read 2 more answers

Help pls do not look it up thank you if u r here snog, pls help thx guys

jekas [21]

Answer:

Evan is incorrect.

Step-by-step explanation:

20 ÷ 25 =

0.8 =

0.8 × 100% =

80%;

Good luck buddy!

8 0

3 years ago

Read 2 more answers

A square pyramid has a base with an area of 20 square meters, and its lateral faces have a slant height of x meters. Sydney is c

svetoff [14.1K]

1. Consider the pyramid ABCDE in the figure 1 attached:

Each side of the square base equals $\sqrt{20} = \sqrt{4*5} = \sqrt{4}* \sqrt{5}=2 \sqrt{5}$ (units)

Area of 1 lateral side of pyramid ABCDE is $\frac{1}{2}* 2 \sqrt{5}*x=\sqrt{5}x$

so the total lateral area is $4\sqrt{5}x$ (units squared)

and the total surface area is $20+4\sqrt{5}x$ (units squared)

2. Now consider the second figure KLMNP, Sydney's pyramid:

The lateral area is $4* \frac{1}{2}* 4 \sqrt{5} *2x=16 \sqrt{5}x$

so the total area of the second pyramid is $20+16 \sqrt{5}x$

So 2 things can be said about the areas:

i) the lateral area of Sydney's pyramid is $\frac{16 \sqrt{5}x}{4\sqrt{5}x} =4$ times larger than the lateral area of the original pyramid.

ii) The total area of Sydney's pyramid is $(20+16 \sqrt{5}x)-(20+4\sqrt{5}x)=12\sqrt{5}x$ units squared larger than the total area of the original pyramid.

5 0

3 years ago

Read 2 more answers