Answer: two or more different pure substances, which may be elements or compounds.
Explanation:
The term varieties of matter is kind of ambiguos since it is not defined.
The best approach to the question is to think of matter as it can be classified into to kinds: pure substaces and mixtures.
Elements and compounds are pure substances.
Elements are pure substances constituted by only one kind of atoms. An element cannot be divided into simpler substances either by physical or chemical media.
A compound is a chemical combination of two or more different elements. A compound can be divided into simpler substances by chemical reactions, but not by physical media. The properties of compounds are different of those of the elements of which they are constituted. The composition of a compoind (ratio among its elements) is fixed.
A mixture is the physical combination of two or more pure substances (either different elements or compounds) which can be mixed in any proportion. This is, its composition is variable. The substances that form the mixture can be separated by physical media.
5.20 mol C6H12* (84.2 g/mol C6H12)= 4.38*10^(2) g C6H12.
The answer should only have three significant figures, according to the numbers in the problem.
Hope this is helpful~
CaO
does not decompose easily.
Explanation:
Calcium oxide is chemically and physically stable at high temperatures.
Maybe you are looking for the decomposition of
CaCO
3
to
CaO
?
That would be
CaCO
3
→
CaO
+
CO
2
Solubility and temperatures are directly related. The higher the temperature of the solvent, the higher the solubility of the solute in the solvent.
Dissolving a solute in a solvent is an endothermic process hence providing heat favors the process. Higher temperatures cause the molecules of the solvent to have high kinetic energy hence bombard each other and with that of the solute with high frequency. This then ensures fast diffusion of the solute particles in the solvent.
The correct equation
for the overall reaction can simply be obtained by adding the two separate
equations together. Now when you add the two equations together, the overall K can
be calculated by multiplying the individual K values. Therefore:<span>
K(overall) = K1 * K2 </span>
K(overall) = (1.6 x
10^-10) * (1.5 x 10^7)
<span>K(overall) = 2.4 x
10^-3</span>
