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nlexa [21]
3 years ago
7

The solubility of silver chloride can be increased by dissolving it in a solution containing ammonia. agcl (s) ag+ (aq) + cl- (a

q) k1 = 1.6 x 10-10 ag+ (aq) + 2nh3 (aq) ag(nh3)2+ (aq) k2 = 1.5 x 107 what is the value of the equilibrium constant for the overall reaction? agcl (s) + 2nh3 (aq) ag(nh3)2+ (aq) + cl- (aq) knet = ?
Chemistry
2 answers:
Sunny_sXe [5.5K]3 years ago
8 0

Answer:

K_{net}=[Cl^-]*[Ag(NH_3)_2^{+2}]=2.4*10^{-3}

Explanation:

Silver chloride dissosation equation:

AgCl \longrightarrow Ag^+ + Cl^-

K_1=[Ag^+]*[Cl^-]

Reaction with ammonia:

Ag^+ + 2 NH_3 \longrightarrow Ag(NH_3)_2^{+2}

K_2=\frac{[Ag(NH_3)_2^{+2}]}{[Ag^+]}

Overall reaction:

AgCl + 2 NH_3 \longrightarrow Ag(NH_3)_2^{+2} + Cl^-

K_{net}=K_1 * K_2

K_{net}=[Ag^+]*[Cl^-]*\frac{[Ag(NH_3)_2^{+2}]}{[Ag^+]}

K_{net}=[Cl^-]*[Ag(NH_3)_2^{+2}]

K_{net}=1.6*10^{-10}*1.5*10^7=2.4*10^{-3}

e-lub [12.9K]3 years ago
3 0

The correct equation for the overall reaction can simply be obtained by adding the two separate equations together. Now when you add the two equations together, the overall K can be calculated by multiplying the individual K values. Therefore:<span>

K(overall) = K1 * K2 </span>

K(overall) = (1.6 x 10^-10) * (1.5 x 10^7)

<span>K(overall) = 2.4 x 10^-3</span>

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