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nlexa [21]
3 years ago
7

The solubility of silver chloride can be increased by dissolving it in a solution containing ammonia. agcl (s) ag+ (aq) + cl- (a

q) k1 = 1.6 x 10-10 ag+ (aq) + 2nh3 (aq) ag(nh3)2+ (aq) k2 = 1.5 x 107 what is the value of the equilibrium constant for the overall reaction? agcl (s) + 2nh3 (aq) ag(nh3)2+ (aq) + cl- (aq) knet = ?
Chemistry
2 answers:
Sunny_sXe [5.5K]3 years ago
8 0

Answer:

K_{net}=[Cl^-]*[Ag(NH_3)_2^{+2}]=2.4*10^{-3}

Explanation:

Silver chloride dissosation equation:

AgCl \longrightarrow Ag^+ + Cl^-

K_1=[Ag^+]*[Cl^-]

Reaction with ammonia:

Ag^+ + 2 NH_3 \longrightarrow Ag(NH_3)_2^{+2}

K_2=\frac{[Ag(NH_3)_2^{+2}]}{[Ag^+]}

Overall reaction:

AgCl + 2 NH_3 \longrightarrow Ag(NH_3)_2^{+2} + Cl^-

K_{net}=K_1 * K_2

K_{net}=[Ag^+]*[Cl^-]*\frac{[Ag(NH_3)_2^{+2}]}{[Ag^+]}

K_{net}=[Cl^-]*[Ag(NH_3)_2^{+2}]

K_{net}=1.6*10^{-10}*1.5*10^7=2.4*10^{-3}

e-lub [12.9K]3 years ago
3 0

The correct equation for the overall reaction can simply be obtained by adding the two separate equations together. Now when you add the two equations together, the overall K can be calculated by multiplying the individual K values. Therefore:<span>

K(overall) = K1 * K2 </span>

K(overall) = (1.6 x 10^-10) * (1.5 x 10^7)

<span>K(overall) = 2.4 x 10^-3</span>

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3 years ago
Which of the following statements describes a difference between a chemical change and a physical change in a substance
siniylev [52]

Explanation:

A physical change is one that alters the physical properties of matter (particularly the form and state).

A chemical change is one in which new kind of matter is formed. It is always accompanied by energy changes (evolution or absorption of energy in form of heat or light or both).

Now, the salient differences between physical and chemical changes;

  1. Physical changes are easily reversible whereas chemical changes are not easily reversible.
  2. Physical changes lead to the production of no new kinds of matter whereas chemical changes leads to the production of new kinds of matter.
  3. Physical changes involves no change in mass whereas chemical changes involves change in mass.
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Why do heart diseas patient's eat oil instead of fat?​
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8 0
3 years ago
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the concentration of the radio active isotope potassium-40 in a rock sample is found to be 6.25%. what is the age of the rock
julsineya [31]

Answer:

5.0 x 10⁹ years.

Explanation:

  • It is known that the decay of a radioactive isotope isotope obeys first order kinetics.
  • Half-life time is the time needed for the reactants to be in its half concentration.
  • If reactant has initial concentration [A₀], after half-life time its concentration will be ([A₀]/2).
  • Also, it is clear that in first order decay the half-life time is independent of the initial concentration.
  • The half-life of K-40 = 1.251 × 10⁹ years.

  • For, first order reactions:

<em>k = ln(2)/(t1/2) = 0.693/(t1/2).</em>

Where, k is the rate constant of the reaction.

t1/2 is the half-life of the reaction.

∴ k =0.693/(t1/2) = 0.693/(1.251 × 10⁹ years) = 5.54 x 10⁻¹⁰ year⁻¹.

  • Also, we have the integral law of first order reaction:

<em>kt = ln([A₀]/[A]),</em>

where, k is the rate constant of the reaction (k = 5.54 x 10⁻¹⁰ year⁻¹).

t is the time of the reaction (t = ??? year).

[A₀] is the initial concentration of (K-40) ([A₀] = 100%).

[A] is the remaining concentration of (K-40) ([A] = 6.25%).

∴ (5.54 x 10⁻¹⁰ year⁻¹)(t) = ln((100%)/( 6.25%))

∴ (5.54 x 10⁻¹⁰ year⁻¹)(t) = 2.77.

∴ t = 2.77/(5.54 x 10⁻¹⁰ year⁻¹) = 5.0 x 10⁹ years.

8 0
3 years ago
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He rate constant of a reaction is 4.55 × 10−5 l/mol·s at 195°c and 8.75 × 10−3 l/mol·s at 258°c. what is the activation energy o
Xelga [282]

Answer : The activation energy of the reaction is, 17.285\times 10^4kJ/mole

Solution :  

The relation between the rate constant the activation energy is,  

\log \frac{K_2}{K_1}=\frac{Ea}{2.303\times R}\times [\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_1 = initial rate constant = 4.55\times 10^{-5}L/mole\text{ s}

K_2 = final rate constant = 8.75\times 10^{-3}L/mole\text{ s}

T_1 = initial temperature = 195^oC=273+195=468K

T_2 = final temperature = 258^oC=273+258=531K

R = gas constant = 8.314 kJ/moleK

Ea = activation energy

Now put all the given values in the above formula, we get the activation energy.

\log \frac{8.75\times 10^{-3}L/mole\text{ s}}{4.55\times 10^{-5}L/mole\text{ s}}=\frac{Ea}{2.303\times (8.314kJ/moleK)}\times [\frac{1}{468K}-\frac{1}{531K}]

Ea=17.285\times 10^4kJ/mole

Therefore, the activation energy of the reaction is, 17.285\times 10^4kJ/mole

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3 years ago
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