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3 years ago

8 5- 8. Solve: (4-2)(6 - 5)

Mathematics

2 answers:

Bingel [31]3 years ago

7 0

Answer:

Step-by-step explanation:

$(4-2)(6 - 5)\\\\Follow\:the\:PEMDAS\:order\:of\:operations\\\\\mathrm{Calculate\:within\:parentheses}\:\left(4-2\right)\::\quad 2\\=2\left(6-5\right)\\\\\mathrm{Calculate\:within\:parentheses}\:\left(6-5\right)\::\quad 1\\=2\times\:1\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:2\times\:1\:\\:\quad 2$

Reika [66]3 years ago

6 0

Answer:

Step-by-step explanation:

Since this expression contains no variable, you can't "solve it."

All y ou can do is to "evaluate it."

(4 - 2) becomes 2 and (6 - 5) becomes 1.

Thus, (4-2)(6 - 5) = (2)(1) = 2

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Alex is feeling stressed this morning. He did not get enough sleep because a dog barked most of the night. The dog barked from 1

inna [77]

Answer:

Poor Alex, I know how they feel, I got a dog myself.

The amount of time between

11:41 pm to 12:09 am is

19 minutes (to 12 am, 60 minutes to next hour) + 9

which is 28 minutes for the first dog barking session

the second time is 35 minutes,

using same method as before.

adding the two separte barking sessions we get

35+28= 63 minutes

which is equivelant to 1 hour and 3 minutes.

In conclusion the dog barks for 1 hour and 3 minutes in total.

7 0

2 years ago

Analyze the following pattern: 1, 2, 5, 10, 17,...

Burka [1]

Step-by-step explanation: Begin by studying the pattern.

Notice that the 1 + 1 is 2, 2 + 3 is 5, 5 + 5 is 10, and 10 + 7 is 17.

So thus far, we're adding 1, 3, 5, and 7. Notice that each of these numbers have a difference of 2 so we would add 9 to get to next number and so on.

4 0

4 years ago

PLEASE HELP WITH ALGEBRA

ratelena [41]

y - y₁ = m(x - x₁)
y - (-7) = -1¹/₅(x - (-3))
y + 7 = -1¹/₅(x + 3)
y + 7 = -1¹/₅(x) - 1¹/₅(3)
y + 7 = -1¹/₅x - 3³/₅

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{-17 - (-2)}{3 - (-9)} = \frac{-17 + 2}{3 + 9}} = \frac{-15}{12} = \frac{-5}{4} = -1\frac{1}{4}$

y - y₁ = m(x - x₁)
y - (-2) = -1¹/₄(x - (-9))
y + 2 = -1¹/₄(x + 9)
y + 2 = -1¹/₄(x) - 1¹/₄(9)
y + 2 = -1¹/₄x - 11¹/₄
- 2 - 2
y = -1¹/₄x - 13¹/₄

y - y₁ = m(x - x₁)
y - (-3) = ⁻¹/₄(x - 8)
y + 3 = ⁻¹/₄(x) + ¹/₄(8)
y + 3 = ⁻¹/₄x + 2
- 3 - 3
y = ⁻¹/₄x - 1

y - y₁ = m(x - x₁)
y - (-17) = ¹/₂(x - (-6))
y + 17 = ¹/₂(x + 6)
y + 17 = ¹/₂(x) + ¹/₂(6)
y + 17 = ¹/₂x + 3
- 17 - 17
y = ¹/₂x - 14

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{-4 - 8}{-4 - 6} = \frac{-12}{-10} = \frac{12}{10} = \frac{6}{5} = 1\frac{1}{5}$

y - y₁ = m(x - x₁)
y - 8 = 1¹/₅(x - 6)
y - 8 = 1¹/₅(x) - 1¹/₅(6)
y - 8 = 1¹/₅x - 7¹/₅
+ 8 + 8
y = 1¹/₅x + ⁴/₅

5 0

4 years ago

Evaluate 9x + 3xy − 2 for x = 3 and y = −3.

klemol [59]

Answer:

- 2

Step-by-step explanation:

Given

9x + 3xy - 2

Substitute x = 3 and y = - 3 into the expression

= 9(3) + 3(3)(- 3) - 2

= 27 - 27 - 2 = - 2

5 0

4 years ago

Find the point(s) on the ellipse x = 3 cost, y = sin t, 0 less than or equal to t less than or equal to 2pi closest to the point

Lady_Fox [76]

Answer and Step-by-step explanation:

The computation of points on the ellipse is shown below:-

Distance between any point on the ellipse

$(3 cos t, sin t) and (\frac{4}{3},0) is\\\\ d = \sqrt{(3 cos\ t - \frac{4}{3}^2) } + (sin\ t - 0)^2\\\\ d^2 = (3 cos\ t - \frac{4}{3})^2 + sin^2 t$

To minimize

$d^2, set\ f' (t) = 0\\\\2(3cos\ t - \frac{x=4}{3} ).3(-sin\ t) + 2sin\ t\ cos\ t = 0\\\\ 8 sin\ t - 16 sin\ t\ cos\ t = 0\\\\ 8 sin\ t (1 - 2 cos\ t) = 0\\\\ sin\ t = 0, cos\ t = \frac{1}{2} \\\\ t= 0, \ 0, \pi,2\pi,\frac{\pi}{3} , \frac{5\pi}{3}$