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kobusy [5.1K]
3 years ago
8

8 5- 8. Solve: (4-2)(6 - 5)

Mathematics
2 answers:
Bingel [31]3 years ago
7 0

Answer:

<h2>2</h2>

Step-by-step explanation:

(4-2)(6 - 5)\\\\Follow\:the\:PEMDAS\:order\:of\:operations\\\\\mathrm{Calculate\:within\:parentheses}\:\left(4-2\right)\::\quad 2\\=2\left(6-5\right)\\\\\mathrm{Calculate\:within\:parentheses}\:\left(6-5\right)\::\quad 1\\=2\times\:1\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:2\times\:1\:\\:\quad 2

Reika [66]3 years ago
6 0

Answer:

2

Step-by-step explanation:

Since this expression contains no variable, you can't "solve it."

All y ou can do is to "evaluate it."

(4 - 2) becomes 2 and (6 - 5) becomes 1.  

Thus, (4-2)(6 - 5) = (2)(1) = 2

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n = 4/5 * 10/3

n = 8/3

n = 2 2/3
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<em>1</em>

Step-by-step explanation:

It only has 1 symmetry line. It's the line that connects the vertex of the vertex angle of the triangle to the midpoint of the base of the triangle.

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Ymorist [56]
I'll do a and e on the first one to show you how to do it

Then See if you can do the rest

a. 6(-3)<span><span>
</span></span>
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So 6 × 3 = 18 ; but since there is a negative on the 3 your answer will be -18

e. -20 ÷ 5

same for this; 20 ÷ 5 = 4, but since the 20 is negative the answer will be <span>-4

You do b, c, d, and f on the first question. Tell me what you get and we'll go from there

</span>Now for the second question <span>

</span>I will do a and d to show you how to do this then you do the rest<span> (I'm inserting a picture with these)

</span>a. 4(-2 \frac{1}{3}) + 7 \frac{1}{6}
First go ahead and turn the fractions into improper fractions, this makes them a bit easier to work with. When multiplying fractions; they do not need a common denominator, all you do is multiply top by top and bottom by bottom.<span>
However, when you add and subtract fractions you MUST have a common denominator

</span>d. (-4.25)(2) + (-4.25)(-2)
remember from the first problem a negative times a positive gives you a negative<span>

but when you times a negative by a negative you get a positive


Now you try b and c; let me know what you get, and we'll go from there!

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