All categories

4 years ago

Reba is making a tablecloth for the dessert table. She needs to

Mathematics

2 answers:

Travka [436]4 years ago

7 0

Answer:

Step-by-step explanation:

autumn leaf.....4.99 per yd.....she needs 3.6 yds

so her cost is : 4.99 x 3.6 = 17.964 rounds to $ 17.96

turkey print.....5.75 per yd....she needs 3.6 yds

so her cost is : 5.75 x 3.6 = $ 20.70

ycow [4]4 years ago

5 0

Answer:

i think the answer would be 21 dollars for 5.75 x 3.6.

5.00 x 3.6 equals to 17.96

all together about 38.96 or 40

Step-by-step explanation:

You might be interested in

Which item is NOT a savings instrument?

quester [9]

Answer with explanation:

A: Treasury Bond: In treasury bond interest is paid till that duration until the bond completely matures. When the period of bond gets over, Actual amount or Par Amount is Returned.

⇒A Saving Instrument.

B. C D

Compact Disc. A type of device that can store data, that is Nanotechnology is used to store more than 500 MB of data.

C: Saving Account

In saving Account, you can deposit and withdraw money at any time ,any day, with the evolution of new technology.

D: Checking Account

Same with the checking account,you can withdraw and deposit money any time on a day.

→Option A, C and D are , types of account , related with currency that is money, but option B, is term related to data.

Option B: →C D is not a Saving Instrument.

6 0

3 years ago

Why are people on here and its Saturday, and its about to be 9

Varvara68 [4.7K]

Answer:

maybe they are about to visit you or kill you or maybe something else

5 0

2 years ago

Suppose that the universal set is U={1,2,3,4,5,6,7,8,9,10}. Express each of the following subsets with bit strings (of length 10

Vladimir [108]

Answer:

0011100000

1010010001

0111001110

Step-by-step explanation:

As the question is not complete, Here is the complete question.

Suppose that the universal set is U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Express each of these sets with bit strings where the ith bit in the string is 1 if i is in the set and 0 otherwise.

a) {3, 4, 5}

b) {1, 3, 6, 10}

c) {2, 3, 4, 7, 8, 9}.

So, we need to express a) b) and c) into bit strings.

Firstly, number of elements in the universal set represent the number of bits in the bit string.

Secondly, 1 = yes element is present in both universal set as well as in sub set.

0 = No, element is not present in sub set but present in universal set.

Hence, we have:

a) Sub set {3,4,5} = 0011100000 (As there are 3 1's which means only 3,4,5 are present in both universal set and subset.

Similarly,

b) Sub set {1, 3, 6, 10} = 1010010001

c) Sub set {2, 3, 4, 7, 8, 9} = 0111001110

5 0

3 years ago

Faye used a stopwatch to find that in 352 minutes, she read 88 pages.

erik [133]

88 pages = 352 minutes
1 page = 352/88 = 4 minutes
4 minutes = 240 seconds.

For Faye to read 1 page, it took her 240 seconds

8 0

3 years ago

Rachel runs 2km to her bus stop, and then rides 4.5 km to school. On average, the bus is 45 km/h faster than Rachel's average ru

Mice21 [21]

Answer:6.042km/h 6km/h approximately

Step-by-step explanation:

First off we have to know the formula relating speed, distance and time which is

Speed = distance/time

Now we are looking for Rachel's running speed

We are to find Rachel's running speed, so let's label is x

We are given that the distance Rachel runs to her bus stop is 2km

We were not given the time she uses to run to the bus stop

So let's label the time Rachel uses to run to her bus stop as y

So from the formula speed = distance/time

We have x = 2/y

Now we are told that the speed the bus uses to get to school is 45km/h faster than her speed used to run

So speed of bus = 45 + x

And the overall time for the whole journey is 25mins, changing this to hours, because the speed details given is in km/h we divide 25 by 60 which will give 0.417

Now if the total time is 0.417 hours, and we labeled the time for Rachel to run to the bus as y, so the time for the time for the bus to get to school will be 0.417 - y

We are also told the bus rides for 4.5km to school

So adding this together to relate the speed, distance and time of the bus with the formula speed = distance/time

We get 45 + x = 4.5/(0.417 - y)

So we have two equations

x = 2/y (1)

45+x = 4.5/(0.417-y) (2)

So putting (1) in (2) we have

45 + (2/y) = 4.5/(0.417-y)

Expanding further

(45y + 2)/y = 4.5(0.417-y)

Cross multiplying

(45y + 2)(0.417 - y) = 4.5y

Opening the brackets

18.765y - 45y2 + 0.834 - 2y = 4.5y

Collecting like terms

-45y2 + 18.765y -2y - 4.5y + 0.834 = 0

-45y2 + 12.265 + 0.834 = 0

Dividing all sides by -45 to make the coefficient of y2 1

y2 - 0.273y - 0.019 = 0

Now we have gotten a quadratic equation, and since it's with decimal numbers we can use either completing the square method of almighty formula

I'm using almighty formula her

For solving

ax2 + bx + c = 0

x = (-b +-root(b2-4ac)/2a

For our own equation, we are finding y

From our our quadratic equation

a = 1, b=-0.273, c = -0.834

you = (-(-0.273)+-root(-0.273-4(1)(-0.019))/2(1)

y = (273+-root(0.151))/2

y = (0.273+0.389)/2 or (0.273-0.389)/2

y = 0.331 or -0.085

So we use the positive answer which is 0.331, because time can't be negative

Then we put y = 0.331 in (1)

x = 2/y

x = 2/0.331

x = 6.042km/h

x = 6km/h approximately

4 0

3 years ago