Answer:
Step-by-step explanation: (Equation 2) = 12(-12+9y/4) - 10y = -8
-144+108y/4 - 10y = -8
-144 + 108y - 40y/4 = -8
-144 + 108y - 40y = -32
108y - 40y = -32+144
68y = 112
Y= 1.64
2-4x+9y=14
12x-10y= -8
2-14+9y = 4x
-12 + 9y = 4x ( equation 3)
(Put in equation 2)
(4.5,6) that is what i got.
Let y(t) represent the level of water in inches at time t in hours. Then we are given ...
y'(t) = k√(y(t)) . . . . for some proportionality constant k
y(0) = 30
y(1) = 29
We observe that a function of the form
y(t) = a(t - b)²
will have a derivative that is proportional to y:
y'(t) = 2a(t -b)
We can find the constants "a" and "b" from the given boundary conditions.
At t=0
30 = a(0 -b)²
a = 30/b²
At t=1
29 = a(1 - b)² . . . . . . . . . substitute for t
29 = 30(1 - b)²/b² . . . . . substitute for a
29/30 = (1/b -1)² . . . . . . divide by 30
1 -√(29/30) = 1/b . . . . . . square root, then add 1 (positive root yields extraneous solution)
b = 30 +√870 . . . . . . . . simplify
The value of b is the time it takes for the height of water in the tank to become 0. It is 30+√870 hours ≈ 59 hours 29 minutes 45 seconds
Answer:
Is is geometric. The geometric ratio is -4
Step-by-step explanation:
3 × -4 = -12
-12 × -4 = 48
48 × -4 = -192
