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Free_Kalibri [48]

2 years ago

15

A ball weighs 15 pounds on Earth and 5.7 on Mars. What is the constant proportionality between the weight of an object on Mars a

nd Earth?

1 answer:

Feliz [49]2 years ago

3 0

The object weighs 5.7 pounds on Mars and 15 pounds on Earth.
Our ratio for Mars weight to Earth weight= 5.7:15 = 2.9:5

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What is the greatest common factor GCF of 10 and four

Pani-rosa [81]

Answer:

Take the numbers 50 and 30. Their greatest common factor is 10, since 10 is the greatest factor that both numbers have in common. To find the GCF of greater numbers, you can factor each number to find their prime factors, identify the prime factors they have in common, and then multiply those together.

Step-by-step explanation:

3 0

3 years ago

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Please help!! This is for a test!!

masya89 [10]

Cos=(adjacent/hypotenuse)
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3 years ago

A pair of shoes has an original price of $65 but is on sale for a 20 percent discount. What number can you multiply by $65 to ge

Contact [7]

Answer:

0.8

Step-by-step explanation:

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2 years ago

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Place the following objects in order from greatest to least gravitational force. Explain your answer.

kozerog [31]

well when thinking of gravity you have to think of the size and mass of the object so,

The sun (largest and most mass)

Earth

Earth's moon

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7 0

3 years ago

Which expression represents the number 2i4−5i3+3i2+−81‾‾‾‾√ rewritten in a+bi form?

vichka [17]

Answer:

The expression $-1+14i$ represents the number $2i^4-5i^3+3i^2+\sqrt{-81}$ rewritten in a+bi form.

Step-by-step explanation:

The value of $i$ is $i=\sqrt{-1}[tex] or [tex]i^{2}=-1[\tex].Now [tex]i^{4}$ in term of $i^{2}[\tex] can be written as, [tex]i^{4}=i^{2}\times i^{2}$

Substituting the value,

$i^{4}=\left(-1\right)\times \left(-1\right)$

Product of two negative numbers is always positive.

$\therefore i^{4}=1$

Now $i^{3}$ in term of $i^{2}[\tex] can be written as, [tex]i^{3}=i^{2}\times i$

Substituting the value,

$i^{3}=\left(-1\right)\times i$

Product of one negative and one positive numbers is always negative.

$\therefore i^{3}=-i$

Now $\sqrt{-81}$ can be written as follows,

$\sqrt{-81}=\sqrt{\left(81\right)\times\left(-1\right)}$

Applying radical multiplication rule,

$\sqrt{ab}={\sqrt{a}}\sqrt{b}$

$\sqrt{\left(81\right)\times\left(-1\right)}={\sqrt{81}}\sqrt{-1}$

Now, $\sqrt{\left(81\right)=9$ and $\sqrt{-1}}=i$

$\therefore \sqrt{\left(81\right)\times\left(-1\right)}=9i$

Now substituting the above values in given expression,

$2i^4-5i^3+3i^2+\sqrt{-81}=2\left(1\right)-5\left(-i\right)+3\left(-1\right)+9i$

Simplifying,

$2+5i-3+9i$

Collecting similar terms,

$2-3+5i+9i$

Combining similar terms,

$-1+14i$

The above expression is in the form of a+bi which is the required expression.

Hence, option number 4 is correct.

5 0

3 years ago