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hammer [34]
4 years ago
13

A fountain holds 12,500 gallons of water. Joe wants to find how many liters that is. Which proportion could he use to solve for

the number of liters?
(
1

L
=
0
.
26

gal
)
A.
1

L
0
.
26

gal
=
12
,
500

gal
x

L
B.
0
.
26

gal
1

L
=
1

gal
12
,
500

L
C.
3
.
79

L
1

gal
=
12
,
500

gal
x

L
D.
1

gal
3
.
79

L
=
12
,
500

gal
x

L
Mathematics
1 answer:
DedPeter [7]4 years ago
4 0

Answer:

The proportion <u>1 L : 0.26 gal = x L : 12500 gal</u>.

Step-by-step explanation:

Given:

A fountain holds 12,500 gallons of water.

1 L = 0.26 gal

Now, to get the proportion to solve for the number of litres.

1\ L : 0.26\ gal = x\ L:12500\ gal

\frac{1\ L}{0.26\ gal} =\frac{x\ L}{12500\ gal}

<em>On solving :</em>

x=12500(\frac{1}{0.26})\ L

Therefore, the proportion <u>1 L : 0.26 gal = x L : 12500 gal</u>.

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Answer:

1. 20% - add 2 lbs of water to get 2.5 lbs of syrup

2. 25% - add 1.5 lbs of water to get 2 lbs of syrup

3. 1.5% - add 32.833 lbs of water to get 33.333 lbs of syrup

Step-by-step explanation:

Ella has 0.5 lbs of sugar. Let x lbs be the amount of water Ella should add to get the syrup.

1. 20% syrup:

0.5 lbs - 20%

x+0.5 lbs - 100%

Write a proportion:

\dfrac{0.5}{x+0.5}=\dfrac{20}{100}\\ \\0.5\cdot 100=(x+0.5)\cdot 20\\ \\50=20x+10\\ \\20x=50-10\\ \\20x=40\\ \\x=2\ lbs

To get 20% syrup Ella should add 2 lbs of water. The total weight of strup is 2.5 lbs.

2. 25% syrup:

0.5 lbs - 25%

x+0.5 lbs - 100%

Write a proportion:

\dfrac{0.5}{x+0.5}=\dfrac{25}{100}\\ \\0.5\cdot 100=(x+0.5)\cdot 25\\ \\50=25x+12.5\\ \\25x=50-12.5\\ \\25x=37.5\\ \\x=1.5\ lbs

To get 25% syrup Ella should add 1.5 lbs of water. The total weight of strup is 2 lbs.

3. 1.5% syrup:

0.5 lbs - 1.5%

x+0.5 lbs - 100%

Write a proportion:

\dfrac{0.5}{x+0.5}=\dfrac{1.5}{100}\\ \\0.5\cdot 100=(x+0.5)\cdot 1.5\\ \\50=1.5x+0.75\\ \\1.5x=50-0.75\\ \\1.5x=49.25\\ \\x=\dfrac{49.25}{1.5}\approx 32.833\ lbs

To get 1.5% syrup Ella should add 32.833 lbs of water. The total weight of strup is 33.333 lbs.

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