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tatiyna
3 years ago
15

WILL GIVE BRAINLY PLEASE HELP!!!!!!!

Mathematics
1 answer:
marta [7]3 years ago
7 0

Answer:

r² = 0.5652  < 0.7 therefore, the correlation between the variables does not imply causation

Step-by-step explanation:

The data points are;

X,          Y

0.7,       1.11

21.9,     3.69

18,         4

16.7,      3.21

18,         3.7

13.8,      1.42

18,          4

13.8,      1.42

15.5,      3.92

16.7,       3.21

The correlation between the values is given by the relation

Y =   b·X + a

b = \dfrac{N\sum XY - \left (\sum X  \right )\left (\sum Y  \right )}{N\sum X^{2} - \left (\sum X  \right )^{2}}

a = \dfrac{\sum Y - b\sum X}{N}

Where;

N = 10

∑XY = 499.354

∑X = 153.1

∑Y = 29.68

∑Y² = 100.546

∑X² = 2631.01

(∑ X)² = 23439.6

(∑ Y)² = 880.902

From which we have;

b = \dfrac{10 \times 499.354 -153.1 \times 29.68}{10 \times 2631.01 - 23439.6} = 0.1566

a = \dfrac{29.68 - 0.1566 \times 153.1}{10} = 0.5704

r = \dfrac{N\sum XY - \left (\sum X  \right )\left (\sum Y  \right )}{\sqrt{\left [N\sum X^{2} - \left (\sum X  \right )^{2} \right ]\times \left [N\sum Y^{2} - \left (\sum Y  \right )^{2} \right ]}}

r = \dfrac{10 \times 499.354 -153.1 \times 29.68}{\sqrt{\left (10 \times 2631.01 - 23439.6  \right )\times \left (10 \times 100.546- 880.902\right )}  } = 0.7518

r² = 0.5652  which is less than 0.7 therefore, there is a weak relationship between the variables, and it does not imply causation.

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Answer:

39-1.96\frac{1}{\sqrt{25}}=38.608    

39+1.96\frac{1}{\sqrt{25}}=39.392    

So on this case the 95% confidence interval would be given by (38.608;39.392)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

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\mu population mean (variable of interest)

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n=25 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The margin of error is given by:

ME= z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

And replacing we got:

ME= 1.96 *\frac{1}{\sqrt{25}}= 0.392

Now we have everything in order to replace into formula (1):

39-1.96\frac{1}{\sqrt{25}}=38.608    

39+1.96\frac{1}{\sqrt{25}}=39.392    

So on this case the 95% confidence interval would be given by (38.608;39.392)    

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