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inessss [21]
3 years ago
6

A freight carrier charges $0.80 for the first ounce plus an additional $0.25 for every ounce (or part of an ounce) over the firs

t ounce. A company is shipping a package weighing 5 ounces. What is the cost for them to ship this package?
Mathematics
1 answer:
Jobisdone [24]3 years ago
3 0

Answer:

$1.80

Step-by-step explanation:

5 ounces

1st ounce = .80¢ plus 25¢ for every other ounce. You have 4 ounces left. 25¢ times 4. = $1.00

$1.00

+0.80

_____

$1.80

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Write the phrase as an expression. Then evaluate the expression when y=20 . the quotient of 40 and the difference of a number y
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Write the phrase as an expression. Then evaluate the expression when y=20 . the quotient of 40 and the difference of a number y and 16 Expression: When y=20, the value of the expression is

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2 years ago
If f(x)= x-3/x and g(x)= 5x-3, what is the domain of (f•g)(x)
ad-work [718]

f(x)=\dfrac{x-3}{x},\ D_f:x\neq0\\\\g(x)=5x-3,\ D_g=\mathbb{R}\\\\(f\cdot g)(x)=f(x)\cdot g(x)\\\\(f\cdot g)(x)=\dfrac{x-3}{x}\cdot(5x-3)=\dfrac{(x-3)(5x-3)}{x}\\\\D_{(f\cdot g)}=D_f

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D=\mathbb{R}-\{0\}

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3 years ago
Find the volume of the region between the planes x plus y plus 2 z equals 2 and 4 x plus 4 y plus z equals 8 in the first octant
Alex787 [66]

Find the intercepts for both planes.

Plane 1, <em>x</em> + <em>y</em> + 2<em>z</em> = 2:

y=z=0\implies x=2\implies (2,0,0)

x=z=0\implies y=2\implies(0,2,0)

x=y=0\implies 2z=2\implies z=1\implies(0,0,1)

Plane 2, 4<em>x</em> + 4<em>y</em> + <em>z</em> = 8:

y=z=0\implies4x=8\implies x=2\implies(2,0,0)

x=z=0\implies4y=8\impliesy=2\implies(0,2,0)

x=y=0\implies z=8\implies(0,0,8)

Both planes share the same <em>x</em>- and <em>y</em>-intercepts, but the second plane's <em>z</em>-intercept is higher, so Plane 2 acts as the roof of the bounded region.

Meanwhile, in the (<em>x</em>, <em>y</em>)-plane where <em>z</em> = 0, we see the bounded region projects down to the triangle in the first quadrant with legs <em>x</em> = 0, <em>y</em> = 0, and <em>x</em> + <em>y</em> = 2, or <em>y</em> = 2 - <em>x</em>.

So the volume of the region is

\displaystyle\int_0^2\int_0^{2-x}\int_{\frac{2-x-y}2}^{8-4x-4y}\mathrm dz\,\mathrm dy\,\mathrm dx=\displaystyle\int_0^2\int_0^{2-x}\left(8-4x-4y-\frac{2-x-y}2\right)\,\mathrm dy\,\mathrm dx

=\displaystyle\int_0^2\int_0^{2-x}\left(7-\frac72(x+y)\right)\,\mathrm dy\,\mathrm dx=\int_0^2\left(7(2-x)-\frac72x(2-x)-\frac74(2-x)^2\right)\,\mathrm dx

=\displaystyle\int_0^2\left(7-7x+\frac74 x^2\right)\,\mathrm dx=\boxed{\frac{14}3}

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Answer:

c^{2} - d^{2} =(c+d)(c-d)  

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Scott and Mark are going to see a movie. The clocks show when the movie begins and ends.
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The elapsed time is B, 2 hours and 25 minutes.
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3 years ago
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