All categories

3 years ago

What’s the volume of this triangular prism ?

Mathematics

2 answers:

Romashka-Z-Leto [24]3 years ago

8 0

Answer:

157.5

Step-by-step explanation:

The first step is to find the area of the triangular base. The formula for the area of a triangle is bh/2, or in this case 5×7/2=17.5. Multiplying this by the length of the prism, you get 9×17.5=157.5. Hope this helps!

iris [78.8K]3 years ago

4 0

Answer: 157.5

Step-by-step explanation: To get the volume of an object you must multiply the width x height ÷ it by 2 x length

Therefore 7 x 5 = 35 ÷ 2 = 17.5

17.5 x 9 = 157.5

You might be interested in

Find the volume of the region bounded above by the elliptical paraboloid zequals=9 minus 4 x squared minus 5 y squared9−4x2−5y2

Virty [35]

Answer:

$\int\limits^1_0 \int^1_0{z} \, dA$

Step-by-step explanation:

$\int\limits^1_0\int^1_0 {9-4x^2-5y^2dy} \, dx$

$\int\limits^1_0 {9y-4x^2y-\frac{5y^3}{3}|_0 ^1 } \, dx$

$\int\limits^1_0 {22/3 -4x^2} \, dx$

You finish the leftover.

7 0

3 years ago

The velocity v and maximum height h of the water being pumped into the air are related by the equation v=\sqrt(2gh) where g is t

Whitepunk [10]

The velocity v and maximum height h of the water being pumped into the air are related by the equation

v= $\sqrt{2gh}$

where g = 32

(a) To find the equation that will give the maximum height of the water , solve the equation for h

v= $\sqrt{2gh}$

Take square root on both sides

$v^2$ = 2gh

Divide by 2g on both sides

$\frac{v^2}{2g}$ = h

So maximum height of the water h = $\frac{v^2}{2g}$

(b) Maximum height h= 80

velocity v= 75 ft/sec

Given g = 32

h = $\frac{v^2}{2g}$

h = $\frac{75^2}{2*32}$

h= 87.89 ft

The pump withe the velocity of 75 ft/sec reaches the maximum height of 87.89 feet. 87.86 is greater than the maximum height 80 feet.

So the pump will meet the fire department needs.

8 0

3 years ago

Simplify 5(2) x 5(5)x5

anastassius [24]

First you would have to multiply everything by the parenthesis
5*2=10
5*5=25
So your equation should look like this
10*25*5
Then multiply from left to right
10*25=250
250*5=1250
So the simplified form of this is 1250

Hope this helps!

3 0

3 years ago

Read 2 more answers

In the library on a university campus, there is a sign in the elevator that indicates a limit of 16 persons. In addition, there

lesya692 [45]

Answer:

15.87% probability that a random sample of 16 people will exceed the weight limit

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For sums, the theorem can be applied, with mean $n*\mu$ and standard deviation $s = \sqrt{n}*\sigma$

In this problem, we have that:

$n = 16, \mu = 16*150 = 2400, s = \sqrt{16}*27 = 108$

If a random sample of 16 persons from the campus is to be taken, what is the chance that a random sample of 16 people will exceed the weight limit

This is 1 subtracted by the pvalue of Z when X = 2508. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$