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3241004551 [841]
3 years ago
6

Divide 1/4 and 3 PLEASE HELP FAST

Mathematics
2 answers:
Eduardwww [97]3 years ago
8 0

Answer:

12

Step-by-step explanation:

1/4 = .25

3 / .25 = 12

plz mark brainliest if helpful

omeli [17]3 years ago
3 0

Answer:

.83

Step-by-step explanation:

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What are the domain and range of the function f(x)=-3(x-5)squared+4
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Domain is all real numbers
range
hmm
we know that x^2=a positive number
then multiply it by that negative -3
therefor the range is going to be mostly negative
if we make the x-5  equal to zero, then there is no negative, so
wher x=5, then f(5)=0+4=4
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How do you solve systems of equations using matrices? I need help with the steps please
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The objective function is simply a function that is meant to be maximized. Because this function is multivariable, we know that with the applied constraints, the value that maximizes this function must be on the boundary of the domain described by these constraints. If you view the attached image, the grey section highlighted section is the area on the domain of the function which meets all defined constraints. (It is all of the inequalities plotted over one another). Your job would thus be to determine which value on the boundary maximizes the value of the objective function. In this case, since any contribution from y reduces the value of the objective function, you will want to make this value as low as possible, and make x as high as possible. Within the boundaries of the constraints, this thus maximizes the function at x = 5, y = 0.

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3 years ago
Jamar's teacher told him that one of the reasons he gave on the proof below was incorrect. Which reason did he make the mistake
Kamila [148]

Answer:

Reason given in step 2. is incorrect. It should read; "Distributive Property."

Step-by-step explanation:

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Which of the following illustrates a phase shift?
Natasha_Volkova [10]

<u>Answer:</u>

A. y = -2 - cos(x-π)


<u>Explanation:</u>

<u>The general form of the trig equation is:</u>

y = A sin (Bx + C) + D

where:

A is the amplitude

\frac{2\pi}{B} is the period

\frac{-C}{B} is the phase shift

D is the vertical shift


<u>Now, let's check the choices:</u>

<u>A. y = -2 - cos(x-π)</u>

\frac{-C}{B} = \frac{\pi}{1}  = \pi

Therefore, the function has a phase shift of π


<u>B. y = 3 cos(4x)</u>

\frac{-C}{B} = \frac{0}{4} = 0

Therefore, the function has no phase shift


<u>C. y = tan(2x)</u>

\frac{-C}{B} = \frac{0}{2} = 0

Therefore, the function has no phase shift


<u>D. y = 1 + sin(x)</u>

\frac{-C}{B} = \frac{0}{1} = 0

Therefore, the function has no phase shift


<u>Based on the above,</u> the correct answer is A


Hope this helps :)

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3 years ago
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