A polynomial that has these factors could be

.
Domain is all real numbers
range
hmm
we know that x^2=a positive number
then multiply it by that negative -3
therefor the range is going to be mostly negative
if we make the x-5 equal to zero, then there is no negative, so
wher x=5, then f(5)=0+4=4
the highest positive number you can get is f(5)=4
so therfor
domain=all real number
range is x≤4
The objective function is simply a function that is meant to be maximized. Because this function is multivariable, we know that with the applied constraints, the value that maximizes this function must be on the boundary of the domain described by these constraints. If you view the attached image, the grey section highlighted section is the area on the domain of the function which meets all defined constraints. (It is all of the inequalities plotted over one another). Your job would thus be to determine which value on the boundary maximizes the value of the objective function. In this case, since any contribution from y reduces the value of the objective function, you will want to make this value as low as possible, and make x as high as possible. Within the boundaries of the constraints, this thus maximizes the function at x = 5, y = 0.
Answer:
Reason given in step 2. is incorrect. It should read; "Distributive Property."
Step-by-step explanation:
The reason given to go from :
2 (3x +4) = 56 to 6x + 8 = 56
is NOT "Multiplication Property of Equality" because one is not multiplying both sides of the equality by a number. The property that is being used is the Distributive Property on the left side of the equation in order to remove the grouping symbols (parenthesis) performing the implied multiplication of the external factor times each term of the binomial in parenthesis.
<u>Answer:</u>
A. y = -2 - cos(x-π)
<u>Explanation:</u>
<u>The general form of the trig equation is:</u>
y = A sin (Bx + C) + D
where:
A is the amplitude
is the period
is the phase shift
D is the vertical shift
<u>Now, let's check the choices:</u>
<u>A. y = -2 - cos(x-π)</u>

Therefore, the function has a phase shift of π
<u>B. y = 3 cos(4x)</u>

Therefore, the function has no phase shift
<u>C. y = tan(2x)</u>

Therefore, the function has no phase shift
<u>D. y = 1 + sin(x)</u>

Therefore, the function has no phase shift
<u>Based on the above,</u> the correct answer is A
Hope this helps :)