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1 year ago

What is the that is located in the number line between 30 and 50

Mathematics

1 answer:

Illusion [34]1 year ago

5 0

Answer: 40?

Step-by-step explanation: I don't quite understand your question fully

You might be interested in

How do I Round 53879 to the nearest hundred.

Elenna [48]

So,

53,879 rounded to the nearest hundred:

If the number in the tens place is greater than or equal to 5, then round up. If not, round down.

7 is greater than or equal to 5, so round up.

53,879 --> 53,900

3 0

3 years ago

Read 2 more answers

At a high school, the length of a class period is 40 minutes. What is the length, in hours, of a class period at the high school

olga2289 [7]

Answer:

40 minutes

2/3 hours

0.667 hour

2,400 seconds

Step-by-step explanation:

5 0

3 years ago

What is the GCF of 36 and 90

ELEN [110]

The greatest common factor is 18

8 0

3 years ago

Read 2 more answers

While riding her bike to the ocean and back home 5 times, Kimberly timed herself at 53min, 48min, 56min, 54min, and 45min. She h

alex41 [277]

Answer:

Kim will need to spend 67 minutes on her sixth ride

Step-by-step explanation:

Represent the number of minutes of her sixth ride by m.

Then the average number of minutes is

53 + 43 + 56 + 54 + 45 + m

---------------------------------------- = 53

Multiplying both sides of this equation by 6 yields

6(53 + 43 + 56 + 54 + 45 + m)

--------------------------------------------- = 6(53)

which simplifies to

251 + m

---------------- = 318

or 251 + m = 318. Subtract 251 from both sides to obtain the value of m:

m = 318 - 251 = 67

Kim will need to spend 67 minutes on her sixth ride to attain an average ride length of 53 minutes.i

4 0

3 years ago

You have a wire that is 20 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The o

Aleksandr [31]

Answer:

Therefore the circumference of the circle is $=\frac{20\pi}{4+\pi}$

Step-by-step explanation:

Let the side of the square be s

and the radius of the circle be r

The perimeter of the square is = 4s

The circumference of the circle is =2πr

Given that the length of the wire is 20 cm.

According to the problem,

4s + 2πr =20

⇒2s+πr =10

$\Rightarrow s=\frac{10-\pi r}{2}$

The area of the circle is = πr²

The area of the square is = s²

A represent the total area of the square and circle.

A=πr²+s²

Putting the value of s

$A=\pi r^2+ (\frac{10-\pi r}{2})^2$

$\Rightarrow A= \pi r^2+(\frac{10}{2})^2-2.\frac{10}{2}.\frac{\pi r}{2}+ (\frac{\pi r}{2})^2$

$\Rightarrow A=\pi r^2 +25-5 \pi r +\frac{\pi^2r^2}{4}$

$\Rightarrow A=\pi r^2\frac{4+\pi}{4} -5\pi r +25$

For maximum or minimum $\frac{dA}{dr}=0$

Differentiating with respect to r

$\frac{dA}{dr}= \frac{2\pi r(4+\pi)}{4} -5\pi$

Again differentiating with respect to r

$\frac{d^2A}{dr^2}=\frac{2\pi (4+\pi)}{4}$ > 0

For maximum or minimum

$\frac{dA}{dr}=0$

$\Rightarrow \frac{2\pi r(4+\pi)}{4} -5\pi=0$

$\Rightarrow r = \frac{10\pi }{\pi(4+\pi)}$

$\Rightarrow r=\frac{10}{4+\pi}$

$\frac{d^2A}{dr^2}|_{ r=\frac{10}{4+\pi}}=\frac{2\pi (4+\pi)}{4}>0$

Therefore at $r=\frac{10}{4+\pi}$ , A is minimum.

Therefore the circumference of the circle is

$=2 \pi \frac{10}{4+\pi}$

$=\frac{20\pi}{4+\pi}$

4 0

3 years ago