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sp2606 [1]
2 years ago
13

The lcm of 165xy and 77x 3 y is _____. 1,155x 3y 11xy 12,705x 4y 2 105x 3y

Mathematics
2 answers:
Karo-lina-s [1.5K]2 years ago
7 0

Answer:

1,155x^3y

Step-by-step explanation:

Find LCM of 165xy \ and \ 77x^3y

We write the expression in factors

165xy= 3 \cdot 11 \cdot 5 \cdot x \cdot y

77x^3y= 11 \cdot 7 \cdot x \cdot x \cdot x \cdot y

To find LCM, w multiply  all the common factors first 11xy

Now we multiply all the remaining terms

LCM = 11xy \cdot 3 \cdot 5 \cdot x \cdot x \cdot 7= 1155x^3y

trapecia [35]2 years ago
4 0
The least common multiple (LCM) can be determined by factoring out the terms first,
                             165xy = (3)(11)(5)(x)(y)
                              77x³y = (7)(11)(x)(x)(x)(y)
Copy the factors writing off the repeated factors only once,
                        LCM = (3)(11)(5)(x)(y)(7)(x)(x)= 1155x³y
The answer is 1155x³y (first choice) 
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Answer:

30 acres of A

0 acres of B

Step-by-step explanation:

On forming the equations we get

Acres = A+B \leq 30  .............(1)

Seed = 5A + 10B \leq 200 ...........(2)

Profit = 160A+50B

Upon rearranging this we get

A= 30-B     sing equation (1)

A=40-2B   using equation (2)

 On plotting these inequalities on the cartesian planes we will get the following points of intersection (0,20) (20,30) (30,0)

Now using these coordinates (A,B) to get Maximum profit

P= $1000 for (0,20)

P=$4700 for (20,30)

P= $4800 for (30,0)

clearly for (30,0) we will get the maximum profit on the crops

3 0
3 years ago
Joseph buys a bag of 60 pieces of taffy. In the bag, there are 6 cinnamon pieces, 18 raspberry pieces, 18 key lime pieces, and t
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Step-by-step explanation:

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Step-by-step explanation:

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Read 2 more answers
A rectangular field with one side along a river is to be fenced. Suppose that no fence is needed along the river, the fence on t
Andreas93 [3]

Answer:

a) Side Parallel to the river: 200 ft

b) Each of the other sides: 400 ft

Step-by-step explanation:

Let L represent side parallel to the river and W represent width of fence.

The required fencing (F) would be F=L+2W.

We have been given that field must contain 80,000 square feet. This means area of field must be equal to 80,000.

LW=80,000...(1)

We are told that the fence on the side opposite the river costs $20 per foot, and the fence on the other sides costs $5 per foot, so total cost (C) of fencing would be C=20L+5(2W)\Rightarrow 20L+10W.

From equation (1), we will get:

L=\frac{80,000}{W}

Upon substituting this value in cost equation, we will get:

C=20(\frac{80,000}{W})+10W

C=\frac{1600,000}{W}+10W

C=1600,000W^{-1}+10W

To minimize the cost, we need to find critical points of the the derivative of cost function as:

C'=-1600,000W^{-2}+10

-1600,000W^{-2}+10=0

-1600,000W^{-2}=-10

-\frac{1600,000}{W^2}=-10

-10W^2=-1,600,000

W^2=160,000

\sqrt{W^2}=\pm\sqrt{160,000}  

W=\pm 400

Since width cannot be negative, therefore, the width of the fencing would be 400 feet.

Now, we will find the 2nd derivative as:

C''=-2(-1600,000)W^{-3}

C''=3200,000W^{-3}

C''=\frac{3200,000}{W^3}

Now, we will substitute W=400 in 2nd derivative as:

C''(400)=\frac{3200,000}{400^3}=\frac{3200,000}{64000000}=0.05

Since 2nd derivative is positive at W=400, therefore, width of 400 ft of the fencing will minimize the cost.

Upon substituting W=400 in L=\frac{80,000}{W}, we will get:

L=\frac{80,000}{400}\\\\L=200

Therefore, the side parallel to the river will be 200 feet.

4 0
3 years ago
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