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Firdavs [7]
3 years ago
6

a storeowner made a list of the number of greeting cards sold last month. The store sold 167 thank you cards, 285 birthday cards

, and 56 blank cards. Based on this data, which number is closest to the probability that the next costumer will buy a blank card?
Mathematics
2 answers:
aniked [119]3 years ago
8 0
Well to solve this we can take 167+285+56=508 then we can take 56/508=.11 to find the probability that the next user will buy a blank card, meaning that there is a 11% probability that the next customer will buy a blank card.

Enjoy!=)
Levart [38]3 years ago
8 0

Answer: There is 11% chance that the next costumer will buy a blank card.

Step-by-step explanation:

Since we have given that

Number of thank you cards = 167

Number of birthday cards = 285

Number of blank cards = 56

So, Total number of cards is given by

167+285+56=508

So, Probability that the next costumer will buy a blank card is given by

\frac{56}{508}\\\\=0.110\times 100\\\\=11\%

Hence, there is 11% chance that the next costumer will buy a blank card.

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3 years ago
What is the probability that you would obtain a sum of 7 or a sum of 11 on the first roll? (Rolling two dice.)
crimeas [40]

Answer:

2/9

Step-by-step explanation:

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7 0
3 years ago
The perimeter of the original rectangle is ______
sergey [27]

Answer:

  • perimter of original rectangle = <u>17. 6 mm</u>
  • side length of the enlarged rectangle = <u>23. 22 mm</u>
  • perimeter of the enlarged rectangle = <u>95. 04 mm</u>

Step-by-step explanation:

<u>PERIMETER</u><u> </u><u>OF</u><u> </u><u>ORIGINAL</u><u> </u><u>RECTANGLE</u>

  • Length of original rectangle = 4.5 mm
  • Width of original rectangle = 4.3 mm

<em>perimeter = 2 × ( length + width)</em>

= 2 × ( 4.5 + 4.3)

= 2 × 8.8

= 17. 6 mm

<u>SIDE</u><u> </u><u>LENGTH</u><u> </u><u>OF</u><u> </u><u>ENLARGED</u><u> </u><u>RECTANGLE</u>

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  • Width of enlarged rectangle = 24.3 mm

Enlargement factor = 24.3 / 4.5

= 5.4

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Side length of enlarged rectangle

= original length × Enlargement factor

= 4.3 × 5.4

= 23. 22 mm

<u>PERIMTER OF ENLARGED RECTANGLE</u>

= 2 × ( enlarged ength + enlarged breadth)

= 2 × (23. 22 + 24. 3 )

= 95. 04 mm

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