1. What is an equation of a line, in point-slope form, that passes through (1,-7) and has a slope of -2/3?
Point Slope form y − y1 = m(x − x1)
Y1: -7 x1:1 slope :-2/3
Y-(-7)=-2/3(x-1)
Y+7=-2/3(x-1)
2. What is the equation of a line, in point-slope form, that passes through (-2,-6) and had a slope of 1/3?
Y-(-6)=1/3(x-(-2))
Y+6=1/3(x+2)
3.What is an equation in point-slope form of the line that passes through the points (4,5) and (-3,-1)
SlopeM: =change in y/change in x
M= -1-5/-3-4
M= -6/-7
M=6/7
So now slope:6/7, point (4,5)
Y-y1=m(x-x1)
Equation in point slope
Y-5=6/7(x-4)
(3×1/2) + (6×3/4) + (3×1) + 1 1/4 +1 1/2=11.75
Answer:
$345
Step-by-step explanation:
15% of 300 is 45. 300 + 45 = 345
Answer:
108 feet²
Step-by-step explanation:
Well we can just multiply the corresponding sides of Quadrilateral ABCD to fit Quadrilateral EFGH.
Line EF is 42 feet
Line FG is 18 feet
Line GH is 18 feet
Line HE is 30 feet
The perimeter of Quadrilateral EFGH is
30+18+18+42=
30+36+42=
66+42=
108 feet²
Answer:
80
Step-by-step explanation:
I remember studying this but forgot the terminology, but basically the line adds up to 180. I believe it was called Adjacent lines or something, but I don't remember. Hope this sparks your memory :)
