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Goryan [66]
4 years ago
12

NEED HELP PLEASE don't know how to solve

Mathematics
1 answer:
amid [387]4 years ago
3 0
The angle formed by the intersection of tangent and secant outside the circle equals half the difference of the <span>intercepted arcs.

</span>\frac{10x+20-80}{2}=2x+15 \\ 10x-60=2(2x+15) \\ 10x-60= 4x+30 \\ 10x-4x=30+60 \\ 6x=90 \\ x=90/6 \\ x=15<span>
</span>
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ASAP BRAINLIEST !! Luis is given the fraction 4/5. He is told to create an equivalent fraction with a numerator of 32. Explain t
solniwko [45]

Answer: answer 40.

Step-by-step explanation:

Note : lets make x the missing denominator.

I would take the 4/5 and set it equals to 32/x

we then cross multiply

where it would be 4 * x = 32  * 5

it would then be 4x = 160

we would then divide 160 by 4

x = 160/ 4

and x would be 40

.... therefore the missing denominator is 40.

8 0
3 years ago
Read 2 more answers
Với mỗi ánh xạ f dưới đây hãy tìm f⁻¹(1)
Daniel [21]

Answer:

a.

Step-by-step explanation:

answer ko dyan is letter a ehh

4 0
3 years ago
What is the term in 3y=7x-9
ehidna [41]
The term in that equation is 3x 7x and -9 hope this helps
7 0
3 years ago
An adult's dinner costs $7. A family of 2 adult's and 2 children pays $22 for their dinners. How many does a child's dinner cost
bonufazy [111]

Answer:

A child's dinner costs $4

Step-by-step explanation:

7 + 7 = 14

22 - 14 = 8

8 / 2 = 4

8 0
3 years ago
The administrator of a $200,000 trust fund must adhere to following guidelines.
skelet666 [1.2K]

Step-by-step explanation:

let us give all the quantities in the problem variable names.

x= amount in utility stock  

y = amount in electronics stock  

c = amount in bond

“The total amount of $200,000 need not be fully invested at any one time.”

becomes

x + y + c ≤ 200, 000,

Also

“The amount invested in the stocks cannot be more than half the total amount invested”

a + b ≤1/2 (total amount invested),

=1/2(x + y + c).

(x+y-c)/2≤0

“The amount invested in the utility stock cannot exceed $40,000”

a ≤ 40, 000

“The amount invested in the bond must be at least $70,000”

 c ≥ 70, 000

Putting this all together, our linear optimization problem is:

Maximize z = 1.09x + 1.04y + 1.05c

subject to

x+ y+ c ≤ 200, 000

x/2 +y/2 -c/2 ≤ 0

              ≤ 40, 000,

              c ≥ 70, 000

a ≥ 0, b ≥ 0, c ≥ 0.

3 0
3 years ago
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