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3 years ago

NEED HELP PLEASE don't know how to solve

Mathematics

1 answer:

amid [387]3 years ago

3 0

The angle formed by the intersection of tangent and secant outside the circle equals half the difference of the <span>intercepted arcs.

</span> $\frac{10x+20-80}{2}=2x+15 \\ 10x-60=2(2x+15) \\ 10x-60= 4x+30 \\ 10x-4x=30+60 \\ 6x=90 \\ x=90/6 \\ x=15$ <span>
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Write the equation of the line that is parallel to y=-0.75x and that passes through the point (8,0)

Mila [183]

Equation of line parallel to y = -0.75x that passes through (8,0) is: y = -0.75x-6

Step-by-step explanation:

Given equation of line is:

$y=-0.75x$

The coefficient of x is the slope of the line so the slope of given line is: -0.75

As parallel lines have equal slopes so the required equation of line will have the same slope.

The slope-intercept form is:

$y = mx+b$

Putting the value of the slope

$y = -0.75x+b$

To find the value of b, putting the point in the equation

$0 = -0.75(8)+b\\0 = -6+b\\b = 6$

Putting the values of m and b, we get

$y = -0.75x-6$

Hence,

Equation of line parallel to y = -0.75x that passes through (8,0) is: y = -0.75x-6

Keywords: Equation of line, Slope-intercept form

Learn more about equation of line at:

#LearnwithBrainly

4 0

3 years ago

What is the unit rate of y=0.75x

Elodia [21]

The unit rate is 0.75

7 0

3 years ago

The equation of a parabola is y=x^2-10x+27. Write the equation in vertex form

azamat

Answer:

$\large \boxed{y = (x - 5)^{2} + 2 }$

Step-by-step explanation:

y = x² - 10x + 27

y = ax² + bx + c

This is the general form of the equation for a parabola.

We must convert it to the vertex form

y = (x - h)² + k, where (h,k) are the coordinates of the vertex.

We can do this by completing the square.

$\begin{array}{rcll}y & = & x^{2} - 10x + 27 & \\y - 27 & = & x^{2} - 10x & \text{Subtracted 27 from each side}\\y - 27&= & x^{2} - 10x + 25 - 25 & \text{Added and subtracted (b/2)}^{2}\\y - 27&= & (x - 5)^{2} - 25 & \text{Wrote the first three terms as the square of a binomial}\\y& = & \mathbf{(x - 5)^{2} + 2} & \text{Added 27 to each side}\\\end{array}\\\text{The vertex form of the parabola is $\large \boxed{\mathbf{y = (x - 5)^{2} + 2 }}$}$ The figure below shows that your parabola has its vertex at (5,2).