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3 years ago

12

NEED HELP PLEASE don't know how to solve

1 answer:

amid [387]3 years ago

3 0

The angle formed by the intersection of tangent and secant outside the circle equals half the difference of the <span>intercepted arcs.

</span> $\frac{10x+20-80}{2}=2x+15 \\ 10x-60=2(2x+15) \\ 10x-60= 4x+30 \\ 10x-4x=30+60 \\ 6x=90 \\ x=90/6 \\ x=15$ <span>
</span>

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3 years ago

Help 15 points!!!!!!!!!!!!!!!!!!!!!

Svetllana [295]

Answer:

see explanation

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan A = $\frac{opposite}{adjacent}$ = $\frac{BC}{AC}$ = $\frac{7}{8}$ , then

∠ A = $tan^{-1}$ ( $\frac{7}{8}$ ) ≈ 41° ( to the nearest degree )

The sum of the angles in the triangle = 180° , then

∠ B + 41° + 90° = 180°

∠ B + 131° = 180° ( subtract 131° from both sides )

∠ B = 49°

Using Pythagoras' identity in the right triangle

AB² = BC² + AC² = 7² + 8² = 49 + 64 = 113 ( take square root of both sides )

AB = $\sqrt{113}$ ≈ 10.6 ( to the nearest tenth )

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2 years ago

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3 years ago

A salesperson works 40 hours per week at a job where she has two options for being paid. Option A is an hourly wage of $20. Opt

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Answer:

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Step-by-step explanation:

they have

20$

5%

40hours

i=prt

multiplication of both

=40×20×5/100

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