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ki77a [65]
3 years ago
5

What is the logarithmic form of 7^5=16,807?

Mathematics
2 answers:
gulaghasi [49]3 years ago
7 0
To go from exponential to logarithmic, you can use e^x=y (exponential) => log_{e} (y)=x (logarithmic). With your specific equation, this would make 7^5=16,807 => log_7(16,807)=5, with that being your logarithmic form.
skelet666 [1.2K]3 years ago
7 0
The last digit (1s place; just to the left of the decimal dot) recurs after the power is 4+.
7⁰⁺⁴ⁿ all have the last digit as '1'.
7¹⁺⁴ⁿ have the last digit as '7'.
7²⁺⁴ⁿ have the last digit as '9'.
7³⁺⁴ⁿ have the last digit as '3'.
7⁴⁺⁴ⁿ, the same as 7⁰⁺⁴ⁿ have the last digit as '1'.
replace the 7 with 16 in the expression. 807
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