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LiRa [457]
3 years ago
10

Math story problem

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
5 0

Answer:

I would say an 80 or 90%

Step-by-step explanation:

ejenwnwks

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I have a question for you does the school cafeteria make it or do the ladies????
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Zhang is designing protective packaging. He tests his design by dropping a raw egg protected by his packaging from various heigh
devlian [24]

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12.

03

Step-by-step explanation:

6 0
3 years ago
Mr. Martinez's limo drove 15 miles south to Candy Land for some delicious gumdrops, then 5 miles east to Chuck E. Cheese for som
jek_recluse [69]

Answer:

15.8 miles

Step-by-step explanation:

Given that:

Distance driven south = 15 miles

Distance driven east = 5 miles

How far is Mr. Martinez from his starting point?

Using Pythagoras :

Distance from starting point(d) :

d = √(15)² + (5)²

d = √225 + 25

d = √250

d = 15.811388

d = 15.8 miles

5 0
3 years ago
Help!! 100 points! (IF SPAM I WILL REPORT YOU AND IF YOU WANT POINTS TYPE FRE ANSWERS IN SEARCH)
iogann1982 [59]

Answer:

Step-by-step explanation:

Part A

Area of a rectangle = length x width

Garden area = 7 3/4 x 2 2/3

= 31/4 x 8/3

= 62/3

= 20 2/3 square feet

Part B

5/8 of the area = 62/3 * 5/8

= 31*5 / 3*12

= 155 / 36

= 4 11/36

The question asks to do so without calculation - the only way is that because the length is approximately 8 feet, section off 5 feet along the length will give an area approximately 5/8 of the total area.

5 0
2 years ago
Help solve for number 6 please !!<br> :)
Semenov [28]

Answer:

x: {-3, 5}

Step-by-step explanation:

Step 1. Find least common denominator

Step 2. Multiply missing factors on top AND bottom

Step 3. Combine like terms

Step 4. Simplify (get rid of denominator)

Step 5. Solve for x

\frac{x}{x-5} +\frac{3}{x+2} =\frac{7x}{x^2-3x-10}            LCD = x^2-3x-10   OR  (x-5)(x+2)

\frac{x}{x-5}(\frac{x+2}{x+2})  +\frac{3}{x+2}(\frac{x-5}{x-5})  =\frac{7x}{x^2-3x-10}

\frac{x(x+2)}{(x-5)(x+2)} +\frac{3(x-5)}{(x+2)(x-5)} =\frac{7x}{(x-5)(x+2)}

\frac{x(x+2)+3(x-5)}{(x-5)(x+2)} =\frac{7x}{(x-5)(x+2)}

\frac{x^2+2x+3x-15}{(x-5)(x+2)} =\frac{7x}{(x-5)(x+2)}

\frac{x^2+5x-15}{(x-5)(x+2)} =\frac{7x}{(x-5)(x+2)}

x^2+5x-15=7x

x^2-2x-15

(x-5)(x+3)

<u>x = -3, 5</u>

8 0
3 years ago
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