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e-lub [12.9K]
3 years ago
13

what do u think the dum.est way to break ur hand is also HELP IN PIC also comment u think is the dum.est way to u

Mathematics
1 answer:
nordsb [41]3 years ago
6 0

Answer: Punch brick wall

Step-by-step explanation:

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Which point is 7 units from (–2, 4)?
Serjik [45]
The distance formula:
d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

(x_1,y_1)=(-2,4) \\
d=7 \\ \\
7=\sqrt{(x-(-2))^2+(y-4)^2} \\
7=\sqrt{(x+2)^2+(y-4)^2} \ \ \ |^2 \\
49=(x+2)^2+(y-4)^2
Check which point satisfies the equation:
(x,y)=(-5,4) \\
49 \stackrel{?}{=} (-5+2)^2+(4-4)^2 \\
49 \stackrel{?}{=} (-3)^2+0^2 \\
49 \stackrel{?}{=} 9 \\
49 \not= 9 \\
doesn't \ satisfy \ the \ equation

(x,y)=(-2,3) \\
49 \stackrel{?}{=} (-2+2)^2+(3-4)^2 \\
49 \stackrel{?}{=} 0^2+(-1)^2 \\
49 \stackrel{?}{=} 1 \\
49 \not= 1 \\
doesn't \ satisfy \ the \ equation

(x,y)=(5,4) \\
49 \stackrel{?}{=} (5+2)^2+(4-4)^2 \\
49 \stackrel{?}{=} 7^2+0^2 \\
49 \stackrel{?}{=} 49 \\
49=49 \\
satisfies \ the \ equation

(x,y)=(9,4) \\
49 \stackrel{?}{=} (9+2)^2+(4-4)^2 \\
49 \stackrel{?}{=} 11^2+0^2 \\
49 \stackrel{?}{=} 121 \\
49 \not= 121 \\
doesn't \ satisfy \ the \ equation

The answer is C.
3 0
4 years ago
I need help on this question
Black_prince [1.1K]

Answer:

4

Step-by-step explanation:

you know what to do with a different person and you know what to do with 33rd grade and you know what to do with your child and your family

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3 years ago
Find the length of the missing side, rounded to the nearest-tenth.<br> 11<br> 9
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Answer:

11=10 9 =10 because 5 or more is bring the number up but 4 or lest it rest

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3 years ago
Find a number such that one-half of the number is 9 less than two-thirds of the number
dimulka [17.4K]
Let's say, the number is "a"
thus        \bf \cfrac{1}{2}a=\cfrac{2}{3}a-9\implies \cfrac{a}{2}=\cfrac{2a}{3}-9\implies \cfrac{a}{2}=\cfrac{2a-27}{3}

cross-multiply and solve for "a"
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Suppose you are an avid reader and are looking to save money on the cost of books Instead of paying about $20 for each book, you
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Answer:

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The answer is 2, because there's comparison of the options of ways to buy books.


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