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beks73 [17]
3 years ago
6

A restaurant had 3 barrels of rice each barrel weighs 12 how many pounds of rice does the restaurant have in all

Mathematics
1 answer:
Kazeer [188]3 years ago
6 0

Answer:

a total of 36 pounds of rice

Step-by-step explanation:

12 times 3 is 36

or

12 plus 12 is 24 plus 12 is 36

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Someone please help!
Natalija [7]

The box plot shows the range and quartiles of the data. It does not show numbers or the mean. The only appropriate choice is

... The lower quartile for the data

3 0
4 years ago
Please tell me correct and​
choli [55]

Answer:

\frac{1}{4} or 0.25 (they're the same)

Step-by-step explanation:

First Part:

  1. 4^{3} = 64  
  2. 8^{2} = 64  
  3. 2 = 2  
  4. Multiply them together: 64 × 64 × 2 = 8192

Second Part:

  1. 2^{7} = 128  
  2. 16^{2} = 256  
  3. Multiply them together: 128 × 256 = 32768

Wrap it all up:

  1. 8192 ÷ 32768 = 0.25 = 1/4

I hope this helps!

7 0
3 years ago
Convert 8x-10y=20 into slope intercept form
4vir4ik [10]

Answer:

y=⅘x-2

Step-by-step explanation:

8x-10y=20

-10y=-8x+20

y=⅘x-2

6 0
3 years ago
Decimal Addition
docker41 [41]

4: 0.99

5: 0.66

6: 0.79

7: 5.2

8: 4.86

9: 4.3

I hope I helped! Also, one thing when you adding decimals or multiplying them, pretend the decimal point isn't even there. Then, once you have your answer, you just add the decimal in the middle. Basically just adding like in first grade! Super easy and I hope I helped!

5 0
3 years ago
A particular fruit's weights are normally distributed, with a mean of 406 grams and a standard deviation of 27 grams.The heavies
Tom [10]

Given

mean of 406 grams and a standard deviation of 27 grams.

Find

The heaviest 14% of fruits weigh more than how many grams?

Explanation

given

mean = 406 gms

standard deviation = 27 gms

using standard normal table ,

\begin{gathered} P(Z>z)=14\% \\ 1-P(Zso , [tex]\begin{gathered} x=z\times\sigma+\mu \\ x=1.08\times27+406 \\ x=435.16 \end{gathered}

Final Answer

Therefore , The heaviest 14% of fruits weigh more than 435.16 gms

8 0
1 year ago
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