A. Area of ABCD - Area of DGA = Area of DEFG
s^2 - 1/2bh = s^2
(5)^2 - 1/2(4)(3) = (3)^2
25 - 1/2(12) = 9
25 - 24 = 9
1 not equal to 9
B. Area of ABCD - Area of GHIA = Area of DGA
s^2 - s^2 = 1/2bh
(5)^2 - (4)^2 = 1/2(4)(3)
25 - 16 = 1/2(12)
9 not equal to 6
C. Area of ABCD + Area of DGA = Area of GHIA
s^2 + 1/2bh = s^2
(5)^2 + 1/2(4)(3) = (4)^2
25 + 1/2(12) = 16
25 + 6 = 16
31 not equal to 16
D. Area of DEFG + Area of GHIA = Area of ABCD
s^2 + s^2 = s^2
(3)^2 + (4)^2 = (5)^2
9 + 16 = 25
25 = 25
The answer is D.
I don't really know what you're trying to ask because
x = -2 and x=6 are your roots.
But if you want to convert them back to their equation form,
get the other side of the equation to be 0.
x = 6
x - 6 = 0
x = -2
x + 2 = 0
so your original equation had something like (x+2)(x-6)
Answer:
c. m∠1 + m∠6 = m∠4 + m∠6
Step-by-step explanation:
Given: The lines l and m are parallel lines.
The parallel lines cut two transverse lines. Here we can use the properties of transverse and find the incorrect statements.
a. m∠1 + m∠2 = m∠3 + m∠4
Here m∠1 and m∠2 are supplementary angles add upto 180 degrees.
m∠3 and m∠4 are supplementary angles add upto 180 degrees.
Therefore, the statement is true.
b. m∠1 + m∠5 = m∠3 + m∠4
m∠1 + m∠5 = 180 same side of the adjacent angles.
m∠3 + m∠4 = 180, supplementary angles add upto 180 degrees.
Therefore, the statement is true.
Now let's check c.
m∠1 + m∠6 = m∠4 + m∠6
We can cancel out m∠6, we get
m∠1 = m∠4 which is not true
Now let's check d.
m∠3 + m∠4 = m∠7 + m∠4
We can cancel out m∠4, we get
m∠3 = m∠7, alternative interior angles are equal.
It is true.
Therefore, answer is c. m∠1 + m∠6 = m∠4 + m∠6
Answer: GR = 27
Step-by-step explanation:
Given: R is the midpoint of FG.
i.e. R bisects FG into two equal parts as FR and GR. [Midpoint divides a line into two equal parts.]
or we can write FR = GR
Since it is given that FR = 27
Then from (i) , GR = FR = 27
i.e. GR = 27
Hence, GR = 27 , which is the required solution.
