Find the standard form of the equation of the parabola with a vertex at the origin and a focus at (0, -4).
1 answer:
We have
Parabola
with vertex (0,0) and focus (0,-4)
we know that
is a vertical parabola that opens down
the standard form of the equation is of the form
(x-h)²=-4p(y-k)
where
(h,k) is the vertex----------> (0,0)
p is the distance from the vertex to the focus or directrix
in this problem
p=4
(x-h)²=-4p(y-k)------> x²=-16y-------> y=-(1/16)x²
the answer is the option
<span>D.)y = negative one divided by sixteen x2
see the attached figure</span>
Parabola
with vertex (0,0) and focus (0,-4)
we know that
is a vertical parabola that opens down
the standard form of the equation is of the form
(x-h)²=-4p(y-k)
where
(h,k) is the vertex----------> (0,0)
p is the distance from the vertex to the focus or directrix
in this problem
p=4
(x-h)²=-4p(y-k)------> x²=-16y-------> y=-(1/16)x²
the answer is the option
<span>D.)y = negative one divided by sixteen x2
see the attached figure</span>
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Answer:
The given fraction reduces to
Step-by-step explanation:
Consider the given fraction
We have to reduce the fraction to the lowest terms.
Consider numerator
We can take x² common from both the term,
Thus, numerator can be written as
Given expression can be rewritten as ,
We can now cancel from both numerator and denominator,
Thus, the given fraction reduces to