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Ber [7]
3 years ago
9

Needs to be graphed and solved please help

Mathematics
1 answer:
il63 [147K]3 years ago
7 0

Answer: here it is graphed and it cant be solved because there are no solutions as seen on the graph!

Step-by-step explanation: hope i helped please mark brainliest!

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What number equals 100 when squared?
vfiekz [6]

Answer: 10

Step-by-step explanation: Remember that squaring a number is multiplying a number by itself. 100 = 10² because 10 x 10 = 100.

8 0
3 years ago
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Please help, see attachment
Black_prince [1.1K]

Answer:

The length of DB is 8

Step-by-step explanation:

I know it doesn't look EXACTLY like the one in the diagram but I just followed the measurements provided

4 0
3 years ago
Solving polynomial(2y-4)(3y+6)​
jeka57 [31]

Answer:

6y² - 24

Step-by-step explanation:

Expand. Follow FOIL method. FOIL =

First

Outside

Inside

Last.

First, multiply the first term of each parenthesis:

2y * 3y = 6y²

Next, multiply the outside terms from both parenthesis:

2y * 6 = 12y

Then, multiply the inside terms from both parenthesis:

-4 * 3y = -12y

Finally, multiply the last terms of each parenthesis:

-4 * 6 = -24

Combine like terms:

6y² + 12y - 12y - 24

6y² + (12y - 12y) - 24

6y² - 24

6y² - 24 is your answer.

~

3 0
4 years ago
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What is the arithmetic sequence in this problem . help plz
adell [148]

Answer:

<u>a(n)=80*(9/10)^(n-1)</u>

Step-by-step explanation:

I think u r confused

this sequence is geometric not arithmetic

HOw we know that ??

when we get a common difference  <u>that must Be equal  </u>

d=72-80=-8  not equal to  d=64.8-72=-7.2

So it is not arithmetic

but when we get the common ratio that also must <u>be equal </u>

r=72/80=9/10 equal to   r=64.8/72=9/10

So it is geometric

By using this equation:

a(n)=a*r^(n-1)

and we have <u>a=80 , r=9/10</u>

Then       <u>a(n)=80*(9/10)^(n-1)</u>

<em>I really hope this helps <3</em>

6 0
3 years ago
find an equation for the nth term of the sequence. -3, -12, -48, -192, ... select one: a. an = 4 • -3n 1 b. an = -3 • 4n - 1 c.
Andrews [41]
-3;-12;-48;-192;...\\\\It's\ the\ geometric\ sequence:a_n=a_1r^{n-1}\\\\a_1=-3;\ a_2=-12\\\\r=a_2:a_1\to r=-12:(-3)=4\\\\\boxed{a_n=-3\cdot4^{n-1}}\to\fbox{b.}
3 0
3 years ago
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