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3 years ago

13

Difference between 783 and 366

2 answers:

Gwar [14]3 years ago

6 0

Difference between 783 and 366:

783 - 366:

7 8 3
-
3 6 6
_____
4 1 7
_____

= 417

Paul [167]3 years ago

5 0

The difference between 783 and 366 is 417.

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Evaluate the integral. (remember to use absolute values where appropriate. Use c for the constant of integration.) 5 cot5(θ) sin

ozzi

$I=5\int \frac{cos^{4}\theta }{sin\theta }\times cos\theta d\theta \\\\I=5\int \left ( 1-sin^{2}\theta \right )^{2}\times \frac{cos\theta }{sin\theta }d\theta \\put\ \sin\theta =t\\\\dt=cos\theta d\theta \\\\I=5\int\frac{t^{4}+1-2t^{2}}{t}dt\ \ \ \ \ \ \ \ \ \ \because (a-b)^2=a^2+b^2-2ab\\\\I=5\left ( \int t^{3}dt + \int \frac{1}{t} -2\int t \right )dt$

by using the integration formula

we get,

$\\I=5\left ( \frac{t^{4}}{4} +logt -t^{2}\right )\\\\I=\frac{5}{4}t^{4}+5\log t-5t^{2}+c$

now put the value of t=\sin\theta in the above equation

we get,

$\int 5\cot^5\theta \sin^4\theta d\theta=\frac{5}{4}sin^{4}\theta+5\log \sin\theta - 5sin^{2} \theta+c$

hence proved

7 0

3 years ago

5. Identify the correct trigonometry formula to use to solve for X.

Anna007 [38]

9514 1404 393

Answer:

(a) cos(55°) = 11/x

Step-by-step explanation:

The marked sides are the hypotenuse (x) and the side adjacent to the given angle (11). Then the relevant trig ratio is ...

Cos = Adjacent/Hypotenuse

cos(55°) = 11/x

4 0

2 years ago

Which of the following describes the parabola with the equation y = −x2 − 3x + 6?

seropon [69]

Answer:

C) The axis of symmetry is x = −1.5 and the vertex is (−1.5, 8.25).

Step-by-step explanation:

The axis of symmetry is x = − b/2a

= -(-3) / 2(-1)

= 3/(-2)

= -1.5

the vertex => x = -1.5

y= -(-1.5)²-3(-1.5)+6 =

-2.25 +4.5+6= 8.25

4 0

3 years ago

5. Mis the midpoint of CD. C has coordinates (-1,-1) and

lana66690 [7]

Answer/Step-by-step Explanation:

4. Midpoint (M) of AB, for A(-2, -3) and B(1, 2) is given as:

$M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})$

Let $A(-2, -3) = (x_1, y_1)$

$B(1, 2) = (x_2, y_2)$

Thus:

$M(\frac{-2 + 1}{2}, \frac{-3 + 2}{2})$

$M(\frac{-1}{2}, \frac{-1}{2})$

5. Given M(3, 5) as midpoint of CD, and C(-1, -1),

let $C(-1, -1) = (x_2, y_2)$

$D(?, ?) = (x_1, y_1)$

$M(3, 5) = (\frac{x_1 +(-1)}{2}, \frac{y_1 +(-1)}{2})$

Rewrite the equation to find the coordinates of D

$3 = \frac{x_1 - 1}{2}$ and $5 = \frac{y_1 - 1}{2}$

Solve for each:

$3 = \frac{x_1 - 1}{2}$

$3*2 = \frac{x_1 - 1}{2}*2$

$6 = x_1 - 1$

$6 + 1= x_1 - 1 + 1$

$7 = x_1$

$x_1 = 7$

$5 = \frac{y_1 - 1}{2}$

$5*2 = \frac{y_1 - 1}{2}*2$

$10 = y_1 - 1$

$10 + 1= y_1 - 1 + 1$

$11 = y_1$

$y_1 = 11$

Coordinates of D is (7, 11)

7 0

3 years ago

Can someone help me<br>

Vladimir79 [104]

Answer:

sure, but what is there to help with?

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers