3 years ago

4x^2-y^2+80x+16y+272=0

Mathematics

1 answer:

Andrew [12]3 years ago

8 0

Answer:

$\frac{4x + 40}{-y +8}$

Step-by-step explanation:

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Use the given facts about the functions to find the indicated limit.

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Step-by-step explanation:

1. You can rewrite it as following:

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This means that you must substitute x=-6 into the limit. There is not x, then the function is always equal to 2, no matter the value of x.

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This means that you must substitute x=-6 into the limit. There is not x, then the function is always equal to 1, no matter the value of x.

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2. Then:

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