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tia_tia [17]
3 years ago
7

How do you solve a-9/a3

Mathematics
1 answer:
Klio2033 [76]3 years ago
5 0
Is it this?
\frac{a - 9}{a3}
If so, then
\frac{a - 9}{a3}  = 0 \\  \frac{a}{a3}  -  \frac{9}{a3}  = 0 \\  \frac{1}{3}   -  \frac{9}{a3}  \\  \frac{1}{3}  =  \frac{9}{a3}  \\ 3( \frac{1}{3} ) = 3( \frac{9}{a3} ) \\ 1 =  \frac{9}{a}  \\ a = 9
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A glacier receded 4 feet a day for a period of 25 days how much shorter was the glacier at the end of the period
KonstantinChe [14]

4*25=100

The glacier was 100 feet shorter than it was originally by the end of the 25 day period.

Hope this helps :)

5 0
3 years ago
Explain weather 14t-3t is equivalent to 3t-14t. Support your sender by evaluating the expression for t=2.
m_a_m_a [10]

Answer:

Solving 14t-3t we get 22 and 3t-14t we get -22

So, 14t-3t is not equivalent to 3t-14t.

Step-by-step explanation:

We need to explain weather 14t-3t is equivalent to 3t-14t. Support your sender by evaluating the expression for t=2.

<em>Equivalent expressions are those that have same values for any value of variable substituted.</em>

Now, We check if our expressions are equivalent, by evaluating the expression for t=2.

If they are equivalent, they would have same result after evaluation.

First, put t=2 into 14t-3t

14t-3t\\Put\:t=2\\=14(2)-3(2)\\=28-6\\=22

Now put t=2, into 3t-14t

3t-14t\\Put\:t=2\\=3(2)-14(2)\\=6-28\\=-22\\

For solving 14t-3t we get 22 and 3t-14t we get -22

So, 14t-3t is not equivalent to 3t-14t.

6 0
3 years ago
If an image of a triangle is congruent to the pre-image, then the scale factor of the dilation must be n=__?
Olin [163]
If the image is congruent to the pre-image, then the scale factor must be 1.
4 0
3 years ago
Read 2 more answers
Factor x3-2x2-9x+18 completely if(x+3) is a factor
Charra [1.4K]

Factor x^3 -2x^2-9x+18

= x^2(x - 2) - 9(x - 2)

= (x^2 - 9)(x -2)

= (x + 3 )(x - 3)(x - 2)

So (x+3) is a factor


6 0
3 years ago
Read 2 more answers
I really need help with b I have already done a
marishachu [46]

Answer:

Step-by-step explanation:

In the first pattern, there were 6 sticks

In the second pattern, there were 10 sticks.

In the third pattern, there were 14 sticks.

Based on the pattern, we see that each time, 4 more sticks are added and that the initial amount of stick is 6.

Thus: the equation for how many sticks there would be in pattern n is:

# of sticks in pattern n = 6 + 4n

Hope that helps!

3 0
3 years ago
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