Number 31 please guys!!!!!

Mathematics

1 answer:

monitta3 years ago

3 0

the answer is c
this is because, first you use the distributive property. Multiply 'y' by the number 3 and you get 3y
then multiply 3 by the number 4.
you get 12
subtract 7 from 12 and you get 5

So, the expression becomes 3y+5

Hope this helped!!

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Use a one-sample t ‑test, based on the data below, to test the null hypothesis H0:µ=100.63 against the alternative hypothesis H1

Sati [7]

Answer:

The standard error (SE) is 0.1847.

The t-statistic for this test is 2.490.

Step-by-step explanation:

We are given that the sample has a mean of $\bar X$ = 101.09 and a standard deviation of s = 0.4887 .

Also, the 7 sample values are also given.

Let $\mu$ = population mean.

So, Null Hypothesis, $H_0$ : $\mu$ = 100.63

Alternate Hypothesis, $H_1$ : $\mu$ > 100.63

The test statistics that would be used here One-sample t test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = 101.09

s = sample standard deviation = 0.4887

n = sample values = 7

The Standard Error (SE) is given by = $\frac{s}{\sqrt{n} }$ = $\frac{0.4887}{\sqrt{7} }$ = 0.1847

So, test statistics = $\frac{101.09-100.63}{\frac{0.4887}{\sqrt{7} } }$ ~ $t_6$

= 2.490

The value of t test statistics is 2.490.

7 0

3 years ago

The equations y = 2x - 5 and y = 13.x

Neporo4naja [7]

Answer:

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Step-by-step explanation:

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2 years ago

Given f(x) = 2x - 1 and g(x) = x^2 + 3x - 1, find f(x) + g(x), f(x) - g(x), f(x) • g(x), and (f/g)(x)

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$\bf \begin{cases}
f(x)=2x-1\\
g(x)=x^2+3x-1
\end{cases}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
f(x)+g(x)\implies (2x-1)+(x^2+3x-1)\implies 2x+3x-1-1+x^2
\\\\\\
x^2+5x-2
\\\\[-0.35em]
~\dotfill$

$\bf f(x)-g(x)\implies (2x-1)-(x^2+3x-1)\implies 2x-1-x^2-3x+1
\\\\\\
-x^2-x
\\\\[-0.35em]
~\dotfill\\\\
f(x)\cdot g(x)\implies (2x-1)\cdot (x^2+3x-1)
\\\\\\
\stackrel{2x(x^2+3x-1)}{2x^3+6x^2-2x}~~+~~\stackrel{-1(x^2+3x-1)}{(-x^2-3x+1)}\implies 2x^3+5x^2-5x+1
\\\\[-0.35em]
~\dotfill\\\\
\cfrac{f(x)}{g(x)}\implies \cfrac{2x-1}{x^2+3x-1}$