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vlabodo [156]
3 years ago
13

the sum of a 3-digit number and a 1-digit number is 217. The product of the numbers is 642. If one number is between 200 and 225

, what are the numbers?
Mathematics
1 answer:
lubasha [3.4K]3 years ago
5 0
I don't know if I'm correct but I'm guessing 216.
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Help with 7-12 please!​
OLEGan [10]

How to solve 7-10: if a coordinate (x, y) is on the line, then f(x) = y.

7. Since x is 6, look at the graph, which shows that y (or f(x)) is 4. (look at picture)

8. Same thing as 7. you will see that f(x) is 15.

9. The other way around. since we know y = 2, looking at the graph shows us that x = 3.

10. Repeat process of 9. x = 10.

How to solve 11 + 12: slope formula (rise-over-run)

11. (14-4)/(12-6) = 10/6 = 5/3.

12. (16-14)/(18-12) = 2/6 = 1/3.

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5 0
3 years ago
Please walk me through this​
FinnZ [79.3K]

Answer:

X is 160. because you can add all the value of x. But first substrate 540 with 100 which is 440. then 1/2x + 1/2x+ (x-15) + (x-25) which is further simplified as x + 2x - 40. then it's further simplified as 3x - 40 = 440. then add 40 with 440 which is 480 then divide it by 3 which is 160. therefore X= 160.

3 0
3 years ago
Find the domain of the function y = 3 tan(23x)
solmaris [256]

Answer:

\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

In other words, the x in f(x) = 3\, \tan(23\, x) could be any real number as long as x \ne \displaystyle \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) for all integer k (including negative integers.)

Step-by-step explanation:

The tangent function y = \tan(x) has a real value for real inputs x as long as the input x \ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

Hence, the domain of the original tangent function is \mathbb{R} \backslash \displaystyle \left\lbrace \left. \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

On the other hand, in the function f(x) = 3\, \tan(23\, x), the input to the tangent function is replaced with (23\, x).

The transformed tangent function \tan(23\, x) would have a real value as long as its input (23\, x) ensures that 23\, x\ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

In other words, \tan(23\, x) would have a real value as long as x\ne \displaystyle \frac{1}{23} \, \left(k\, \pi + \frac{\pi}{2}\right).

Accordingly, the domain of f(x) = 3\, \tan(23\, x) would be \mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

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Which of the following statements must be true in order for the line represented by the equation y = mx + b to have a negative x
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<span>The signs of the values of m and b<span> are the same.</span></span>
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</span>
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