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3 years ago

The equation of a circle is (x−11)2+(y+15)2=144 . What is the circle's radius?

2 answers:

4 0

I am assuming you meant to write the equation as (x-11)^2 + (y+15)^2= 144 in which case the answer is 12. The general formula of a circle is (x-h)^2 + (y-k)^2 = r^2 so the value on the right hand side of the equation is the square of the radius. You simply have to take the square root of it

yuradex [85]3 years ago

3 0

The equation of a circle is (x-h)^2+(y-k)^2=r^2, where (h,k) is the center and r is the radius.
To find the radius, we would find the square root of 144, which is 12.
r=12

:)

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3 years ago

5. What is the multiple zero and multiplicity of f(x) = (x + 4)(x - 2)(x + 4)(x + 4)?

natali 33 [55]

The zeros of this functions are -4, 2, -4, and -4.

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2 years ago

Which equation in slope-intercept form represents a line that passes through the point (6,−1) and is perpendicular to the line y

damaskus [11]

For this case we have that by definition, the equation of a line of the slope-intersection form is given by:

$y = mx + b$

Where:

m: It is the slope of the line

b: It is the cut point with the y axis

By definition, if two lines are perpendicular then the product of their slopes is -1.

If we have: $y = 2x-7$

$m_ {1} = 2\\2 * m 2 = - 1\\m_ {2} = - \frac {1} {2}$

Thus, the equation is of the form:

$y = - \frac {1} {2} x + b$

We substitute the point:

$-1 = - \frac {1} {2} (6) + b\\-1 = - \frac {1} {2} (6) + b\\-1 = -3 + b\\-1 + 3 = b\\b = 2$

Finally, the equation is:

$y = - \frac {1} {2} x + 2$

Answer:

$y = - \frac {1} {2} x + 2$

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3 years ago

Write an equation of the perpendicular bisector of the segment with the endpoints (8,10) and ( -4,2).

ale4655 [162]

Answer:

The required equation is:

$y = -\frac{3}{2}x+9$

Step-by-step explanation:

To find the equation of a line, the slope and y-intercept is required.

The slope can be found by finding the slope of given line segment. A the perpendicular bisector of a line is perpendicular to the given line, the product of their slopes will be -1 and it will pass through the mid-point of given line segment.

Given points are:

$(x_1,y_1) = (8,10)\\(x_2,y_2) = (-4,2)$