Kelly tells you that when variables are in the denominator, the equation becomes unsolvable. "There is a value for x that makes
the denominator zero, and you can't divide by zero," Kelly explains. Using complete sentences, demonstrate to Kelly how the equation is still solvable.
The problem can be translated into an equation that is something like 4/5 + 3/x = 1/2 we cannot have x equal to zero because the number can be infinite. So the LCD here is 10x, so multiply both sides by that to get: 8x + 30 = 5x Subtract 5x and 30 from both sides: 3x = -30 divide: x = -10 The solution isn't zero so there is a solution.
