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3 years ago

The diagonals of a rhombus are _____.

Mathematics

2 answers:

Andre45 [30]3 years ago

8 0

The answer here is parallel

zysi [14]3 years ago

6 0

The diagonals of a rhombus are perpendicular.

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3x-10+5m+6x+7 identify the parts of the following expressions

bulgar [2K]

Answer:

9x+5m-3

Step-by-step explanation:

3x-10+5m+6x+7

3x+6x+5m-10+7

9x+5m-3

7 0

3 years ago

Use the Change of Base Formula to evaluate log3 58. Then convert log3 58 to a logarithm in base 4. Round to the nearest thousand

Natali5045456 [20]

Hello,

$log_3(58)= \dfrac{ln(58)}{ln(3)}=3,69597450... \\

log_3(58)=log_4(x)\\

 \dfrac{ln(58)}{ln(3)} = \dfrac{ln(x)}{4}==\textgreater\ x=e^{ \frac{ln(58)*ln(4)}{ln(3)}}\\

 =167,957104437222249066099...

$

≈167.96

5 0

2 years ago

Read 2 more answers

Solve for . Simplify your answer as much as possible. please help

Sonja [21]

Answer:

$x=-6$

Step-by-step explanation:

So we have the equation:

$-34=7(x+8)+8x$

First, distribute the 7 into the (x+8) and simplify:

$-34=7(x)+7(8)+8x\\-34=7x+56+8x$

Combine the like terms 7x and 8x by adding them together:

$-34=56+15x$

Subtract 56 from both sides to isolate the x:

$-34-56=15x+56-56\\15x=-90$

Divide both sides by 15 to get x:

$x=-90/15=-6$

5 0

3 years ago

Simplify the following expression: -k - 11 - 2 + 2k

gulaghasi [49]

Answer:

k-13

Step-by-step explanation:

brainliest?

5 0

3 years ago

Read 2 more answers

Accuracy in taking orders at a drive-through window is important for fast-food chains. Periodically, QSR Magazine publishes "The

pav-90 [236]

Answer:

a) 0.7412 = 74.12% probability that all the three orders will be filled correctly.

b) 0.0009 = 0.09% probability that none of the three will be filled correctly

c) 0.0245 = 2.45% probability that at least one of the three will be filled correctly.

d) 0.9991 = 99.91% probability that at least one of the three will be filled correctly

e) 0.0082 = 0.82% probability that only your order will be filled correctly

Step-by-step explanation:

For each order, there are only two possible outcomes. Either it is filled correctly, or it is not. Orders are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The percentage of orders filled correctly at Burger King was approximately 90.5%.

This means that $p = 0.905$

You and 2 friends:

So 3 people in total, which means that $n = 3$

a. What is the probability that all the three orders will be filled correctly?

This is P(X = 3).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{3,3}.(0.905)^{3}.(0.095)^{0} = 0.7412$

0.7412 = 74.12% probability that all the three orders will be filled correctly.

b. What is the probability that none of the three will be filled correctly?

This is P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{3,0}.(0.905)^{0}.(0.095)^{3} = 0.0009$

0.0009 = 0.09% probability that none of the three will be filled correctly.

c. What is the probability that one of the three will be filled correctly?

This is P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{3,1}.(0.905)^{1}.(0.095)^{2} = 0.0245$

0.0245 = 2.45% probability that at least one of the three will be filled correctly.

d. What is the probability that at least one of the three will be filled correctly?

This is

$P(X \geq 1) = 1 - P(X = 0)$

With what we found in b:

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0009 = 0.9991$

0.9991 = 99.91% probability that at least one of the three will be filled correctly.

e. What is the probability that only your order will be filled correctly?

Yours correctly with 90.5% probability, the other 2 wrong, each with 9.5% probability. So

$p = 0.905*0.095*0.095 = 0.0082$

0.0082 = 0.82% probability that only your order will be filled correctly

7 0

3 years ago