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yanalaym [24]
2 years ago
6

Round log 58 to the nearest thousandth

Mathematics
2 answers:
Vesnalui [34]2 years ago
6 0

Log 58 = 1.7634


The digit in the ten thousandth place is 4 ⇒ less than 5 , discard


Log 58 = 1.7634 ≈ 1.763


Answer: 1.763

Luda [366]2 years ago
5 0
You have \log(58) = 1.763427.... Rounding this number to the nearest thousandth means to write it as the three-decimal-digits number which is nearest to this one.
The two numbers with three decimal digits are 1.763 and 1.764. Since the fourth decimal digit is 4, your number is closer to 1.763 than 1.764, so this is its approximation.

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Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

First, you need to use a normal distribution table to solve this. If you don't have it, then see the attached table so you can guide yourself.

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To do this, you should calculate first the Z score value for both heights, one for 63 inches and the other with 65 inches. Then, with those values, we'll look the table to get the area under the curve, and thus, the probability. To calculate Z use the following expression:

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x: height required

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Z2 = 65 - 63.6 / (2-5/√75) = 4.85

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5 0
3 years ago
Hi help me with this pls ​
Rudiy27

\huge \underline{ \pink{Answer}}

Refer to the attachments

Attachment (1)

B (1)

Attachment 2

B(2)

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Step-by-step explanation:

ig

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nignag [31]

Step-by-step explanation:

<em>x² - x - 20 = 0</em>

<em>x²</em><em> </em><em>-</em><em> </em><em>(</em><em>5</em><em>-</em><em>4</em><em>)</em><em> </em><em>x </em><em>-</em><em> </em><em>2</em><em>0</em><em> </em><em>=</em><em> </em><em>0</em><em> </em>

<em>x²</em><em> </em><em>-</em><em> </em><em>5x </em><em>+</em><em> </em><em>4x </em><em>-</em><em>2</em><em>0</em><em> </em><em>=</em><em> </em><em>0</em>

<em>x </em><em>(</em><em> </em><em>x </em><em>-</em><em> </em><em>5</em><em>)</em><em> </em><em>+</em><em> </em><em>4</em><em> </em><em>(</em><em> </em><em>x </em><em>-</em><em> </em><em>5</em><em>)</em><em> </em><em>=</em><em> </em><em>0</em>

<em>(</em><em>x </em><em>-</em><em> </em><em>5</em><em>)</em><em> </em><em>(</em><em>x+</em><em> </em><em>4)</em><em> </em><em>=</em><em> </em><em>0</em>

<em>Either</em><em>. </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>

<em>x </em><em>-</em><em> </em><em>5</em><em> </em><em>=</em><em> </em><em>0</em>

<em>x </em><em>=</em><em> </em><em>5</em>

<em>Or, </em>

<em>x </em><em>+</em><em> </em><em>4</em><em> </em><em>=</em><em> </em><em>0</em><em> </em>

<em>x </em><em>=</em><em> </em><em>-</em><em>4</em>

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3 years ago
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