Answer:
y² - (K- 2)y + 2k +1 = 0
equal roots means D=0
D= b^2 - 4ac
a=1, b= (k-2), c= 2k+1
so,
(k-2)^2 - 4(1)(2k+1) = 0
=> k^2 +4 - 8k -4 = 0
=> k^2 -8k = 0
=> k^2 = 8k
=> k= 8k/k
=> k = 8
Therefore the answer is k= 8
Hope it helps........
Answer:
51
Step-by-step explanation:
11+(-7)^2-9 - original
11+49-9 - square the -7, since its in brackets the negative applies too and a negative x a negative = positive, so it ends up as 7x7+49
60-9 - add both positives 11+49=60
51 - subtract 9 from 60, 60-9=51
Answer:
(2a, b )
Step-by-step explanation:
Given the endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is
[ 
(x₁ + x₂ ), (y₁ + y₂ ) ]
Here (x₁, y₁ ) = N(2a, 2b) and (x₂, y₂ ) = P(2a, 0), thus
midpoint = [ (2a + 2a), (2b + 0 ) ] = (2a, b )
That is when h=0
so assuming yo meant
h(t)=-16t²+24t+16
solve for t such that h(t)=0
because when height=0, the gymnast hits the ground
so
0=-16t²+24t+16
using math (imma complete the square
0=-16(t²-3/2t)+16
0=-16(t²-3/2t+9/16-9/16)+16
0=-16((t-3/4)²-9/16)+16
0=-16(t-3/4)²+9+16
0=-16(t-3/4)²+25
-25=-16(t-3/4)²
25/16=(t-3/4)²
sqrt both sides
+/-5/4=t-3/4
3/4+/-5/4=t
if we do plus (because minus would give us negative height)
8/4=t
2=t
it takes 2 seconds
