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Vsevolod [243]
4 years ago
5

Which number should be placed in the blank before o2 to balance the equation? n2 ___o2→2no2?

Physics
2 answers:
stepladder [879]4 years ago
4 0

Answer:

Number  '2' should be placed in the blank before oxygen.

Explanation:

N_2 + O_2\rightarrow 2NO_2

Stoichiometric coefficient is the number mentioned in front of the chemical substances in balanced chemical reaction.

N_2 + 2O_2\rightarrow 2NO_2

According to stoichiometry, 1 mole of nitrogen gas reacts with 2 moles of oxygen gas to give 2 moles of nitrogen dioxide.

Stoichiometric coefficient of nitrogen gas = 1

Stoichiometric coefficient of oxygen gas = 2

Stoichiometric coefficient of nitrogen dioxide gas = 2

k0ka [10]4 years ago
3 0
N2 + 2O2 → 2NO2
The number to be placed before O2 is 2

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4 years ago
A truck travels 1430 m uphill along a road that makes a constant angle of 5.76◦ with the horizontal.
Alex73 [517]

Answer:

The horizontal component of displacement is d' = 1422.7 m

Explanation:

Given data,

The distance covered by the truck, d = 1430 m

The angle formed with the horizontal, Ф = 5.76°

The displacement is a vector quantity.

The horizontal component of displacement is given by,

                                 d' = d cos Ф

                                     = 1430 cos 5.76°

                                     = 1422.7 m

Hence, the horizontal component of displacement is d' = 1422.7 m

5 0
3 years ago
How many pounds is a 1 pound rock?
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Explanation:

6 0
3 years ago
Read 2 more answers
0. A 3.00-kg block is dropped from rest on a vertical spring whose spring constant is 750 N/m. The block hits the spring, compre
Dmitry_Shevchenko [17]

Answer:

the spring compressed is 0.1878 m

Explanation:

Given data

mass = 3 kg

spring constant k = 750 N/m

vertical distance h = 0.45

to find out

How far is the spring compressed

solution

we will apply here law of mass of conservation

i.e

gravitational potential energy loss = gain of eastic potential energy of spring

so we say m×g×h = 1/2× k × e²

so e² = 2×m×g×h / k

so

we put all value here

e² = 2×m×g×h / k

e² = 2×3×9.81×0.45 / 750

e²  = 0.0353

e = 0.1878 m

so the spring compressed is 0.1878 m

5 0
3 years ago
The value of the normal force exerted on a 2,000 gram block on a table
kobusy [5.1K]

Answer:

N = 19.6 N

Explanation:

Given that,

Mass of a block, m = 2000 g

1 kg = 1000 g

It means, 2000 g = 2kg

We need to find the value of normal force on the block on a table. Normal force is balanced by the weight of the block as follows :

N = mg, g is acceleration due to gravity

N = 2 kg × 9.8 m/s²

N = 19.6 N

So, the normal force acting on the block is 19.6 N.

4 0
3 years ago
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