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4 years ago

Which number should be placed in the blank before o2 to balance the equation? n2 ___o2→2no2?

Physics

2 answers:

stepladder [879]4 years ago

4 0

Answer:

Number '2' should be placed in the blank before oxygen.

Explanation:

$N_2 + O_2\rightarrow 2NO_2$

Stoichiometric coefficient is the number mentioned in front of the chemical substances in balanced chemical reaction.

$N_2 + 2O_2\rightarrow 2NO_2$

According to stoichiometry, 1 mole of nitrogen gas reacts with 2 moles of oxygen gas to give 2 moles of nitrogen dioxide.

Stoichiometric coefficient of nitrogen gas = 1

Stoichiometric coefficient of oxygen gas = 2

Stoichiometric coefficient of nitrogen dioxide gas = 2

k0ka [10]4 years ago

3 0

N2 + 2O2 → 2NO2
The number to be placed before O2 is 2

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4 years ago

If position vector r = bt^2i + ct^3j, where b and c are positive constants, when does the velocity vector make an angle of 450 w

vazorg [7]

$\vec r(t)=bt^2\,\vec\imath+ct^3\,\vec\jmath$

The velocity at time $t$ is

$\dfrac{\mathrm d\vec r(t)}{\mathrm dt}=2bt\,\vec\imath+3ct^2\,\vec\jmath$

Take two vectors that point in the positive $x$ and positive $y$ directions, such as $\vec\imath$ and $\vec\jmath$ . The dot products of the velocity vector with $\vec\imath$ and $\vec\jmath$ are

$\dfrac{\mathrm d\vec r(t)}{\mathrm dt}\cdot\vec\imath=2bt=\sqrt{4b^2t^2+9c^2t^4}\cos\theta$

and

$\dfrac{\mathrm d\vec r(t)}{\mathrm dt}\cdot\vec\jmath=3ct^2=\sqrt{4b^2t^2+9c^2t^4}\cos\theta$

We want the angles between these vectors to be 45º, for which we have $\cos45^\circ=\frac1{\sqrt2}$ . So

$\begin{cases}2\sqrt2\,bt=\sqrt{4b^2t^2+9c^2t^4}\\3\sqrt2\,ct^2=\sqrt{4b^2t^2+9c^2t^4}\end{cases}\implies3\sqrt2\,ct^2-2\sqrt2\,bt=0$

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