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vazorg [7]
3 years ago
12

A train moving at a constant speed on a surface inclined upward at 10.0° with the horizontal travels a distance of 400 meters in

5 seconds. Calculate the vertical velocity component of the train during this time period. A. 41.10 meters/second B. 19.23 meters/second C. 13.89 meters/second D. 41.70 meters/second E. 78.78 meters/second
Physics
2 answers:
larisa86 [58]3 years ago
8 0

Answer:

C. 13.89 meters/second

Explanation:

If the velocity of the train is v=s/t, where s is the distance and t is time, then v=400/5=80m/s. To get the vertical component of the velocity we need to multiply the velocity v with a sin(α): Vv=v*sin(α), where Vv is the vertical component of the velocity and α is the angle with the horizontal. So:

Vv=80*sin(10)=80*0.1736=13.888 m/s. 

So the vertical component of the velocity of the train is Vv=13.888 m/s.

kakasveta [241]3 years ago
7 0

Answer:

C.

13.89 meters/second

Explanation:

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v² = 920.52

v = 30.34m/s

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