Question

An 800 V/m electric field is directed along the +x-axis. If the potential at x = 0 m is 2000 V, what is the potential at x = 2 m?

Answer 1

Answer:

400 V

Explanation:

Electric filed , E=800 V/m

$V_1=2000 V$

$x_1=0,x_2=2 m$

We know that

$E=\frac{V_1-V_2}{x_2-x_1}$

Using the formula

$800=\frac{2000-V_2}{2-0}$

$800=\frac{2000-V_2}{2}$

$2000-V_2=800\times 2=1600$

$V_2=2000-1600$

$V_2=400 V$

Hence, the potential at x=2 m=400 V