Answer:
-40
Step-by-step explanation:
f(5)= -(5)^2-3(5)
-25-15=-40
Answer:
-7
Step-by-step explanation:
You use the quadratic formula of
to get:
a = 1
b = 7
c = -13
then you plug that into x= (-b ± √b²-4ac)/(2a) :
x= ( -7 ± √7²- 4(1)(-13) )/(2(1))
![x=-\frac{7}{2} + \frac{\sqrt{101}}{2} \\\\x=-\frac{7}{2} - \frac{\sqrt{101}}{2}](https://tex.z-dn.net/?f=x%3D-%5Cfrac%7B7%7D%7B2%7D%20%2B%20%5Cfrac%7B%5Csqrt%7B101%7D%7D%7B2%7D%20%5C%5C%5C%5Cx%3D-%5Cfrac%7B7%7D%7B2%7D%20-%20%5Cfrac%7B%5Csqrt%7B101%7D%7D%7B2%7D)
The sum of these two x values turns out to be:
![x=-\frac{7}{2} + \frac{\sqrt{101}}{2}+( -\frac{7}{2} - \frac{\sqrt{101}}{2} )= -\frac{14}{2} = 7](https://tex.z-dn.net/?f=x%3D-%5Cfrac%7B7%7D%7B2%7D%20%2B%20%5Cfrac%7B%5Csqrt%7B101%7D%7D%7B2%7D%2B%28%20-%5Cfrac%7B7%7D%7B2%7D%20-%20%5Cfrac%7B%5Csqrt%7B101%7D%7D%7B2%7D%20%29%3D%20-%5Cfrac%7B14%7D%7B2%7D%20%3D%207)
What is the interquartile range of the sequence 5,5,8,8,13,14,16,16,19,22,23,27,31 ?
Romashka-Z-Leto [24]
Answer:
The Interquartile range is 10.
Step-by-step explanation:
First, we will need to find the mean, the mean of this sequence is 16, you will now need to find quartile 1 and quartile 3. Quartile 1 is 13, and quartile 3 is 23. Lastly, subtract Quartile 3 and Quartile 1 will be the answer.
So, 23-13=10
The Answer will be 10, the interquartile range is 10.
Hope this helps!
Answer:
b.
Step-by-step explanation:
5*30+3*45>300
150+135
30+45=75