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Dvinal [7]
3 years ago
8

Write this equation in vertex form. y = x^2 -12x +20

Mathematics
2 answers:
kotegsom [21]3 years ago
8 0

Answer:

y = (x-6) ^ 2 -16

Step-by-step explanation:

The vertex form for a quadratic equation has the following form:

y = (x-h) ^ 2 + k

Where the vertice of the equation is the point (h, k)

To transform the equation y = x ^ 2 -12x +20 in its vertex forms we must find its vertex.

Be a quadratic equation of the form:

ax ^ 2 + bx + c

Where a, b and c are real numbers, then the vertex of the equation will be:

x = - \frac{b}{2a}

For the given equation:

b = -12\\a = 1

Therefore the vertice is:

x = - \frac{-12}{2(1)}\\\\x = 6

Now we substitute x = 6 into the equation and find the value of k.

y = (6) ^ 2 -12 (6) +20\\\\y = -16 = k

Therefore the vertice is: (6, -16)

And the equation is:

y = (x-6) ^ 2 -16

viva [34]3 years ago
7 0

Answer:

y = (x-6)²-16

Step-by-step explanation:

We have given a quadratic equation.

y = x²-12x+20

We have to rewrite above equation in vertex form.

y = a(x-h)²+k is vertex form of quadratic equation.

Adding and subtracting  (-6)² to both sides of above equation, we have

y = x²-12x+20+(-6)²-(-6)²

y = x²-12x+(-6)²+20-(-6)²

y =  (x-6)²+20-36

y = (x-6)²-16

The vertex form is y = (x-6)²-16 where (6,16) is vertex for equation of parabola.

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Could these triangles be congruent? yes, if ab ≅ de yes, if bc = 7 yes, if ab ≅ ef no, because the hypotenuses must have differe
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Checking for Congruency in the Given Triangles

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Read 2 more answers
Consider the polynomial p(x) = x^3 + 4x^2 + 6x − 36.
Nady [450]

Answer:

a. attached graph; zero real: 2

b. p(x) = (x - 2)(x + 3 + 3i)(x + 3 - 3i)

c. the solutions are 2, -3-3i and -3+3i

Step-by-step explanation:

p(x) = x³ + 4x² + 6x - 36

a. Through the graph, we can see that 2 is a real zero of the polynomial p. We can also use the Rational Roots Test.

p(2) = 2³ + 4.2² + 6.2 - 36 = 8 + 16 + 12 - 36 = 0

b. Now, we can use Briott-Ruffini to find the other roots and write p as a product of linear factors.

2 |  1     4     6    -36

     1      6    18     0

x² + 6x + 18 = 0

Δ = 6² - 4.1.18 = 36 - 72 = -36 = 36i²

√Δ = 6i

x = -6±6i/2 = 2(-3±3i)/2

x' = -3-3i

x" = -3+3i

p(x) = (x - 2)(x + 3 + 3i)(x + 3 - 3i)

c. the solutions are 2, -3-3i and -3+3i

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3 years ago
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seropon [69]

4) 247÷19=13

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A social problem can best be described as:
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A.

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an issue that negatively impacts a group of people.

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