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daser333 [38]
3 years ago
8

PLSSS HELP IMMEDIATELY!!!!!!! only answer if u know. i’ll be giving brainiest if u don’t leave a link.

Mathematics
1 answer:
podryga [215]3 years ago
7 0

Answer:

1. isosceles because two of the sides are equal

2. right because there is a right angle

Step-by-step explanation:

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Complete parts a through f below to find nonnegative numbers x and y that satisfy the given requirements. Give the optimum value
MArishka [77]

Answer:

  • y = 81-x
  • the domain of P(x) is [0, 81]
  • P is maximized at (x, y) = (54, 27)

Step-by-step explanation:

<u>Given</u>

  • x plus y equals 81
  • x and y are non-negative

<u>Find</u>

  • P equals x squared y is maximized

<u>Solution</u>

a. Solve x plus y equals 81 for y.

  y equals 81 minus x

__

b. Substitute the result from part a into the equation P equals x squared y for the variable that is to be maximized.

  P equals x squared left parenthesis 81 minus x right parenthesis

__

c. Find the domain of the function P found in part b.

  left bracket 0 comma 81 right bracket

__

d. Find dP/dx. Solve the equation dP/dx = 0.

  P = 81x² -x³

  dP/dx = 162x -3x² = 3x(54 -x) = 0

The zero product rule tells us the solutions to this equation are x=0 and x=54, the values of x that make the factors be zero. x=0 is an extraneous solution for this problem so ...

  P is maximized at (x, y) = (54, 27).

7 0
3 years ago
Can someone help me answer this
Firlakuza [10]

Answer:

maby c

Step-by-step explanation:

tell me if this helps

5 0
2 years ago
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Can someone help me solve this asap ??? thank you :) !!​
vazorg [7]

Answer:

A = 3 ,B = 3

Step-by-step explanation

2^3 × 3^3 × 5

1080

<em><u>Hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>helps</u></em>

8 0
3 years ago
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Write the equation in standard form for the circle that has a diameter with endpoints (6, -9)
nevsk [136]

Answer:

Step-by-step explanation:

By definition a diameter goes through the center of the circle.  So if we find the midpoint of the diameter, we will have the h and k of the center.  Then we will use one of the points ON the circle as x and y and solve for r.  Here goes:

M=(\frac{6+(-6)}{2},\frac{-9+(-9)}{2}) to get a midpoint/center of (0, -9).

The standard form of a circle is

(x-h)^2+(y-k)^2=r^2

Filling in with h, k, x, and y:

(6-0)^2+(-9-(-9))^2=r^2 which simplifies to

6^2+0^2=r^2  so

r^2=36

Now we can write the equation of the circle:

x^2+(y+9)^2=36

7 0
3 years ago
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Please help with 8 and 10
DiKsa [7]

Answer:

x = 28 for 8

and

x = 2 for 10

Step-by-step explanation:

hope it helps

7 0
3 years ago
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