$10.50a + $3.75b = $2,071.50
It is given that b = 82
Therefore - $10.50a + ($3.75)(82) = $2,071.50
or $10.50a + $307.50 = $2,071.50
$10.50a = $2,071.50 - $307.50 = $1,764.00
Therefore - a (number of adult tickets sold) = $1,764.00/$10.50 = 168 tickets
Answer:
3 subtracted from the product of 7 and a number b
3 subtracted= -3
product of 7 and a number b= 7b
put those together:
7b-3
hope this helps, also what grade is this
Answer:
Step-by-step explanation:
f(x)=-4x+2
g(x)=x²+1
(gof)(x)=g(f(x))=g(-4x+2)=(-4x+2)²+2=16x²-16x+4+2=16x²-16x+6
(gof)(3)=16(3)²-16(3)+6=144-48+6=150-48=102
First, apply the distributive property to the left side of the inequality. Multiply each of the two numbers inside the parentheses by 6 and then add those products. Next, subtract -24 from both sides. Then, to get \begin{align*}x\end{align*} by itself on one side of the inequality, you need to divide both sides by 6.
